The initial compression of the spring is determined as 0.54 m.
<h3>What is the compression of the spring?</h3>
The compression of the spring is determined by applying the principle of conservation of linear momentum as follows;
E = U
mgh = ¹/₂kx²
2mgh = kx²
x² = 2mgh/k
x = √(2mgh/k)
where;
- m is the mass of the projetcile
- h is the height
- k is the spring constant = 0.07 N/cm = 7 N/m
- x is the compression of the spring
x = √(2 x 0.021 x 9.8 x 5)/7)
x = 0.54 m
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True. The amount of water on Earth is consistent even if it is displayed in different forms.
Answer:
655 nm
Explanation:
When the intereference is destructive then the thickness, d of antireflective film coating one side is given by
2d=w/2n
Where w is wavelength and n is the reflective index of the film
Making w the subject of formula then
w=4nd
Substituting 1.25 for n and 131 nm for d then the wavelength will be
w=4*1.25*131=655 nm
Therefore, the wavelength is equivalent to 655 nm
Answer:
A mass is suspended on a spring. The spring is compressed so that the mass is located 5 cm above its rest position. The mass is released at time t = 0 and allowed to oscillate. It is observed that the mass reaches its lowest points after it is released. Find an equation that describes the motion of the mass.
1/2
Explanation:
We do not start at y=0y=0 so it is better to use a cosine curve. The hanging string is compressed to a position that is y=5y=5 units above the rest position. Hence, |a|=5∣a∣=5. Also, since we begin at positive values, then a=5a=5.
We begin at the highest point y=5y=5.
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I believe it is velocity, acceleration is in m/sec^2