Answer:
22 N applied force
Explanation: Since they are both pushing the wagon in the same direction the force adds up.
 
        
                    
             
        
        
        
Answer:
F₂= 210 pounds
Explanation:
Conceptual analysis
Hooke's law
Hooke's law establishes that the elongation (x) of a spring is directly proportional to the magnitude of force (F) applied to it, provided that said spring is not permanently deformed:
F= K*x   Formula (1)
Where;
F  is the magnitude of the force applied to the spring in Newtons (Pounds)
K is the elastic spring constant, which relates force and elongation. The higher its value, the more work it will cost to stretch the spring. (Pounds/inch)
x the elongation of the spring (inch)
Data
The data given is incorrect because if we apply them the answer would be illogical.
The correct data are as follows:
F₁ =80 pounds
x₁= 8 inches
x₂= 21  inches
Problem development
We replace data in formula 1 to calculate  K :
F₁= K*x₁
K=( F₁) / (x₁)
K=( 80) / (8) = 10 pounds/ inche
We apply The formula 1 to calculate  F₂
F₂= K*x₂
F₂= (10)*(21)
F₂= 210 pounds
 
        
             
        
        
        
Answer:

Explanation:
Since  , we calculate the resistance rate by deriving this formula with respect to time:
, we calculate the resistance rate by deriving this formula with respect to time:

Deriving what is left (remember that  ):
):

So we have:

Which for our values is (the rate of <em>I(t)</em> is decreasing so we put a negative sign):

 
        
             
        
        
        
Answer:
r = 0.02 m
Explanation:
from the question we have :
speed = 1 rps = 1x 60 = 60 rpm
coefficient of friction (μ) = 0.1
acceleration due to gravity (g) = 9.8 m/s^{2}
maximum distance without falling off (r) = ?
to get how far from the center of the disk the coin can be placed without having to slip off we equate the formula for the centrifugal force with the frictional force on the turntable force
mv^2 / r =  m x g x μ
v^2 / r =  g x μ  .......equation 1
where
velocity (v) = angular speed (rads/seconds) x radius
angular speed (rads/seconds) = (\frac{2π}{60} ) x rpm
angular speed (rads/seconds) = (\frac{2 x π}{60} ) x 60 = 6.28 rads/ seconds
now
velocity = 6.28 x r = 6.28 r
now substituting the value of velocity into equation 1
v^2 / r =  g x μ
(6.28r)^2 / r = 9.8 x 0.1
39.5 x r = 0.98
r = 0.02 m
 
        
             
        
        
        
Answer:
mass =25 kg
using clockwise moment = anticlockwise moment