URGENT!! <br>Question in attachment. <br>thanks

In August 2011, the Juno spacecraft was launched from Earth with the mission of orbiting Jupiter in 2016. The closest distance b

Vikentia [17]

(a) 8927 mi/h

In order to calculate the average speed, we need to convert the time (t=5.0 y) into hours first. In 1 year, we have 365 days, each day consisting of 24 hours, so the time taken is:

$t=(5.0 y)(365 d/y)(24 h/d)=43,800 h$

The distance covered by the spacecraft is

$d=391 mil. mi = 391\cdot 10^6 mi$

Therefore, the average speed is just the ratio between the distance covered and the time taken:

$v=\frac{d}{t}=\frac{391\cdot 10^6 mi}{43,800 h}=8,927 mi/h$

(b) 35 minutes (2097 seconds)

The transmitted signals (which is a radio wave, which is an electromagnetic wave) travels back to the Earth at the speed of light:

$c=3.0\cdot 10^8 m/s$

Since 1 miles = 1609 metres, the distance covered by the signal is

$d=391\cdot 10^6 mi \cdot (1609 m/mi)=6.29\cdot 10^{11} m$

So, the time taken by the signal will be

$t=\frac{d}{v}=\frac{6.29\cdot 10^{11} m}{3.0\cdot 10^8 m/s}=2097 s$

And since 1 minute = 60 sec, the time taken is

$t=2097 s \cdot \frac{1}{60 s/min}\sim 35 min$

7 0

3 years ago

A rigid tank initially contains 1.4 kg saturated liquid water at 200◦C. At this state, 25 percent of the volume is occupied by w

rjkz [21]

Answer:

(a) Volume of the tank is $6.47\times 10^{- 3}\ m^{3}$

(b) Temperature is $371^{\circ}C$

Pressure is 21.3 kPa

(c) The change in internal energy is 1373.54 kJ/kg

Solution:

As per the question:

Mass of liquid in the tank, m = 1.4 kg

Temperature, T = $200^{\circ}C$

Volume occupied by water, V = 25% $V_{t}$ = 0.25 $V_{t}$

Volume occupied by air, V' = 75% $V_{t}$

where

$V_{t}$ = Volume of tank

Now,

(a) In order to calculate the volume of the tank, we make use of the steam table for specific volume at as given temperature:

At $200^{\circ}C$ , the specific volume, v = 0.001157 $m^{3}/kg$

At $200^{\circ}C$ , the internal energy, u = 850.46 kJ/kg

Now, Volume of water, V = mv = $1.4\times 0.001157 = 1.62\times 10^{- 3} m^{3}$

Thus

$V = 0.25V_{t}$

$V_{t} = \frac{1.62\times 10^{- 3}}{0.25} = 6.47\times 10^{- 3}\ m^{3}$

(b) For the final temperature and pressure, we calculate the specific volume, v' and then find the corresponding temperature and pressure from the steam table:

v' = $\frac{V_{t}}{m} = \frac{6.47\times 10^{- 3}}{1.4} = 4.63\times 10^{- 3}\ m^{3}/kg$

The corresponding temperature to this specific volume, T' = $371^{\circ}C$

The corresponding pressure to this specific volume, P' = 21.3 kPa

The corresponding internal energy to this specific volume, u' = 2224 kJ/kg

(c) The change in the internal energy of water is given by:

$\Delta U = u' - u = 2224 - 850.46 = 1373.54 kJ/kg$

3 0

3 years ago

Which example best represents translational kinetic energy?

Lemur [1.5K]

Answer: Option (e) is the correct answer.

Explanation:

There are three types of kinetic energy which are vibrational, rotational and translational kinetic energy.

A plucked string on a guitar will produce sound and it represents vibrational kinetic energy.

The moving blades of a ceiling fan shows the rotation of blades and it represents rotational kinetic energy.

A spinning top also displays rotation therefore, it represents rotational kinetic energy.

A tuning fork struck on a rubber block will produce sound and it will vibrate. Therefore, it represents vibrational kinetic energy.

An apple falling from a tree shows that apple is linearly falls on the ground therefore, it represents translational kinetic energy.

Thus, we can conclude that an apple falling from a tree is the best example which represents translational kinetic energy.

5 0

4 years ago

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Sudhir walk .40 km in a direction 60 degrees west of north then goes .50km due west. what is his displacement?

DENIUS [597]

consider east-west direction along x-axis and north-south direction along y-axis

from the diagram

A = Ax i + By j = - (0.40 Sin60) i + (0.40 Cos60) j = - 0.35 i + 0.20 j

B = Bx i + By j = - 0.50 i + 0 j

Net displacement is given as

D = A + B

D = (- 0.35 i + 0.20 j ) + (- 0.50 i + 0 j )

D = - 0.85 i + 0.2 j

magnitude of displacement is given as

|D| = sqrt((- 0.85)² + (0.2)²)

|D| = 0.87 km

direction of displacement is given as

θ = tan⁻¹(0.2/0.85)

θ = 13.5 deg north of west

5 0

4 years ago

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If the 50 kg objects slows down to a velocity of 1 m/s how much kinetic energy does it have?

Bogdan [553]

It has 50kg with a velocity of 1 m/s times the speed of the cart divided by 2 and multiplied by kinectic x plus 5

3 0

3 years ago

Read 2 more answers

URGENT!! Question in attachment. thanks ​

URGENT!! Question in attachment. thanks