Answer:
32.46m/s
Explanation:
Hello,
To solve this exercise we must be clear that the ball moves with constant acceleration with the value of gravity = 9.81m / S ^ 2
A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are the follow

Where
Vf = final speed
Vo = Initial speed
=7.3m/S
A = g=acceleration
=9.81m/s^2
X = displacement
=51m}
solving for Vf

the speed with the ball hits the ground is 32.46m/s
Answer:
is b and d hope id helpful
Explanation:
idk how to explain
The answer is d.8,120 foot-pounds
Answer:
93 o 39.
Explanation:
Hola.
En este caso, podemos resolver este problema por medio del planteamiento de las siguientes ecuaciones:
1. Definimos <em>x</em> como el primer dígito y <em>y</em> como el segundo, por lo tanto, como su suma es 12, escribimos:
<em>x</em> + <em>y</em> = 12
2. Ahora, dado que el primer dígito, x es el triple del segundo, escribimos:
<em>x</em> = 3 <em>y</em>
De este modo, podemos resolver para <em>y</em>:
3 <em>y</em> + <em>y</em> = 12
4 <em>y</em> = 12
<em>y</em> = 12 / 4
<em>y</em> = 3
Y para <em>x</em>:
<em>x</em> = 3 <em>y</em>
<em>x</em> = 3 * 3
<em>x</em> = 9
Así, el número puede ser 93 o 39.
¡Saludos!
Answer: an isolated system
Explanation: