Answer: Option B. R = (1/2)gt^2
Explanation:
S = R (horizontal distance)
V^2 = 2gS
V^2 = 2gR
R = V^2 / 2g
But V = gt
R = (gt)^2 / 2g
R = (g^2 x t^2) / 2g
R = gt^2 / 2
But t^2 = 2h/g
R = ( g x 2h/g) / 2
R = h
But h = (1/2)gt^2
R = h = (1/2)gt^2
Answer:
<h3>Salinity is the saltiness or amount of salt dissolved in a body of water, called saline water. It is usually measured in g/L or g/kg. </h3>
Crust and atmosphere earth outer crust and the mantel is the most important thing about the mantle are is what it is made up if and last is the core
Explanation:
The given data is as follows.
m = 5000 kg, h = 800 km = 
, r = R + h = 
kg, G = 
As we know that,

v = 
And, it is known that formula to calculate angular velocity is as follows.

v = 
= 
= 
Thus, we can conclude that speed of the satellite is
.
gravitational force of planet exerted on its object near the surface is known as weight
so here we know that gravitational force of mars is much less than the gravitational force of Earth
So on the surface of mars the Weight of objects must be much less than the weight of object on surface of Earth
so here correct answer must be
<em>D. Your weight would decrease.</em>