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3 years ago

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Newton's law of gravitation says that the magnitude f of the force exerted by a body of mass m on a body of mass m is f = gmm r2

where g is the gravitational constant and r is the distance between the bodies. (a) find df/dr.

1 answer:

sergij07 [2.7K]3 years ago

4 0

Hi there u are in town

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4. Which of the following statement is correct regarding velocity and speed of a moving body?

lara31 [8.8K]

Answer:

Explanation:

Hello friend!!!

The correct option is <u><em>(d) Velocity of a moving body is its speed in a given direction.</em></u>

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Suppose a shrimp has been put on the ground that has just been taken out of water.Now touch the shrimp from a distance by a stic

Alex777 [14]

Answer:

yes

Explanation:

I would say yes because it's exerting some type of force as it reacts to the stick to make it jump straight in an upwards direction

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If you we're in charge of designing a wire to cart electricity across your city, state or provide, which of the following proper

OLEGan [10]

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3 years ago

Select Light for the type of wave, adjust the wavelength so that the light is red, and increase the amplitude of the light to th

Sergeu [11.5K]

Answer:

here as we increase the distance the intensity will decrease and hence the amplitude of the electric field will decrease and vice-versa

Explanation:

As wee know that the amplitude of the wave will decide the energy of the wave

Here we know that energy density of electromagnetic wave is given as

$u = \frac{1}{2}\epsilon_0E_0^2$

now we have

$\frac{I}{c} = \frac{1}{2}\epsilon_0 E_0^2$

so here we can say that intensity of the wave at the given distance from the source is given by formula

$I = \frac{P}{4\pi r^2}$

so here as we increase the distance the intensity will decrease and hence the amplitude of the electric field will decrease and vice-versa.

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3 years ago

There is a 50 g sample of Ra-229. It has a half-life of 4 minutes.

Sloan [31]

Via half-life equation we have:

$A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h} }$

Where the initial amount is 50 grams, half-life is 4 minutes, and time elapsed is 12 minutes. By plugging those values in we get:

$A_{final}=50(\frac{1}{2})^\frac{12}{4}=50(\frac{1}{2})^{3}=50(\frac{1}{8})=6.25g$

There is 6.25 grams left of Ra-229 after 12 minutes.

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3 years ago