Yes because the protons are the same but the neutrons change
Answer:
0.76 mole of Fe2S3.
Explanation:
Step 1:
Determination of the number of mole in 449g iron(III)bromide, FeBr3. This is illustrated below:
Mass of FeBr3 = 449g
Molar mass of FeBr3 = 56 + (80x3) = 296g/mol
Mole of FeBr3 =..?
Mole = Mass /Molar Mass
Mole of FeBr3 = 449/296
Mole of FeBr3 = 1.52 moles
Step 2:
The balanced equation for the reaction. This is given below:
2FeBr3 + 3Na2S —> 6NaBr + Fe2S3
Step 3:
Determination of the number of mole of Fe2S3 produced from the reaction of 449g ( i.e 1.52 moles) of FeBr3. This is illustrated below:
From the balanced equation above,
2 moles of FeBr3 reacted to produce 1 mole of Fe2S3.
Therefore, 1.52 moles of FeBr3 will react to produce = (1.52 x 1)/2 = 0.76 mole of Fe2S3.
Therefore, 0.76 mole of Fe2S3 is produced from the reaction.
Answer:
Magnesium, Mgstart text, M, g, end text, is a group 2 element that will form 2+ cations. Because it usually forms cations of only one type, we don't need to specify its charge. We can simply refer to the cation in the ionic compound as magnesium. ... Therefore, the name for the compound is magnesium phosphide.
Explanation:
(this may or not be correct)
-also i finished that drawing you wanted :p-
Answer is: the average atomic mass of 125 atoms of uranium is 235.88.
ω(U-234) = 10 ÷ 125.
ω(U-234) = 0.080.
ω(U-235) = 75 ÷ 125.
ω(U-235) = 0.60.
ω(U-238) = 40 ÷ 125.
ω(U-238) = 0.320.
Average atomic mass of atoms of uranium =
Ar(U-234) · ω(U-234) + Ar(U-235) · ω(U-235) + Ar(U-238) · ω(U-238).
Average atomic mass of atoms of uranium =
234 · 0.08 + 235 · 0.6 + 238 · 0.32.
Average atomic mass of atoms of uranium = 18.72 + 141 + 76.16.
Average atomic mass of atoms of uranium = 235.88.
