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Anestetic [448]
3 years ago
7

What are the steps to go from the names of compounds to the formulas

Chemistry
1 answer:
marysya [2.9K]3 years ago
4 0

Answer:

Explanation:

write down the formulas, use the expressions and formulas to convert

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Atom A has 32 protons and 35 neutrons. atom B has 32 protons and 33 neutrons. are they isotopes?
Anna007 [38]
Yes because the protons are the same but the neutrons change
8 0
3 years ago
Which tool was most likely used in a procedure if the lab report shows that approximately 300 mL of water was used ?
Travka [436]

Graduated Cylinder is the answer to this.


4 0
3 years ago
Read 2 more answers
How many moles of iron(III) sulfide,
Ray Of Light [21]

Answer:

0.76 mole of Fe2S3.

Explanation:

Step 1:

Determination of the number of mole in 449g iron(III)bromide, FeBr3. This is illustrated below:

Mass of FeBr3 = 449g

Molar mass of FeBr3 = 56 + (80x3) = 296g/mol

Mole of FeBr3 =..?

Mole = Mass /Molar Mass

Mole of FeBr3 = 449/296

Mole of FeBr3 = 1.52 moles

Step 2:

The balanced equation for the reaction. This is given below:

2FeBr3 + 3Na2S —> 6NaBr + Fe2S3

Step 3:

Determination of the number of mole of Fe2S3 produced from the reaction of 449g ( i.e 1.52 moles) of FeBr3. This is illustrated below:

From the balanced equation above,

2 moles of FeBr3 reacted to produce 1 mole of Fe2S3.

Therefore, 1.52 moles of FeBr3 will react to produce = (1.52 x 1)/2 = 0.76 mole of Fe2S3.

Therefore, 0.76 mole of Fe2S3 is produced from the reaction.

5 0
3 years ago
If there is only one type of cation that can be formed from an element, what do we do with its name?
KatRina [158]

Answer:

Magnesium, Mgstart text, M, g, end text, is a group 2 element that will form 2+ cations. Because it usually forms cations of only one type, we don't need to specify its charge. We can simply refer to the cation in the ionic compound as magnesium. ... Therefore, the name for the compound is magnesium phosphide.

Explanation:

(this may or not be correct)

-also i finished that drawing you wanted :p-

6 0
3 years ago
what is the average atomic mass of 125 atoms of uranium if there are 10 atomd of U-234, 75 atoms of U-235, and 40 atoms of U-238
zimovet [89]

Answer is: the average atomic mass of 125 atoms of uranium is 235.88.

ω(U-234) = 10 ÷ 125.

ω(U-234) = 0.080.

ω(U-235) = 75 ÷ 125.

ω(U-235) = 0.60.

ω(U-238) = 40 ÷ 125.

ω(U-238) = 0.320.

Average atomic mass of atoms of uranium =

Ar(U-234) · ω(U-234) + Ar(U-235) · ω(U-235) + Ar(U-238) · ω(U-238).

Average atomic mass of atoms of uranium =

234 · 0.08 + 235 · 0.6 + 238 · 0.32.

Average atomic mass of atoms of uranium = 18.72 + 141 + 76.16.

Average atomic mass of atoms of uranium = 235.88.

8 0
3 years ago
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