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Nesterboy [21]
3 years ago
5

Which changes do not involve forming or breaking chemical bonds? rusting and cutting burning and melting burning and digesting b

oiling and melting
Physics
1 answer:
r-ruslan [8.4K]3 years ago
6 0

Answer:

boiling and melting!

Explanation:

These do not make any changes chemically to the substance.

Hope this helps!

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Help pls and thank you PLEASE NO LINKS
AveGali [126]

Answer: mutation

explanation: no other species of its kind will have this mutation

4 0
3 years ago
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Consider an ideal monatomic gas of N particles with mass m in thermal equilibrium at a temperature T. The gas is contained in a
harina [27]

Answer:

K.E.=\dfrac{3}{2}KT

Explanation:

Given that

Number of particle =N

Equilibrium temperature= T

Side of cube = L

Gravitational acceleration =g

The kinetic energy of an atom  given as

K.E.=\dfrac{3}{2}KT

Where

Equilibrium temperature= T

Boltzmann constant =K

        K =1.380649×10−23 J/K

3 0
3 years ago
Mass and weight are the same in<br> meaning and unit.<br><br> true or false
schepotkina [342]

Answer:

False.

Explanation:

Mass is how much space an object takes up, while weight is how light or heavy an object is.

4 0
3 years ago
In a solution , the ______ is the substance that takes in , or dissolve,the other substance
Zepler [3.9K]
Its is solute. The dissolved substance. In salt water, salt is the solute and water is the solvent.

8 0
4 years ago
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An astronaut weighs 8.00 × 102 newtons on the sur- face of Earth. What is the weight of the astronaut 6.37 × 106 meters above th
kolbaska11 [484]

Answer:

mg=200.4 N.

Explanation:

This problem can be solved using Newton's law of universal gravitation: F=G\frac{m_{1}m_{2}}{r^{2}},

where F is the gravitational force between two masses m_{1} and m_{2}, r is the distance between the masses (their center of mass), and G=6.674*10^{-11}(m^{3}kg^{-1}s^{-2}) is the gravitational constant.

We know the weight of the astronout on the surface, with this we can find his mass. Letting w_{s} be the weight on the surface:

w_{s}=mg,

mg=8*10^{2},

m=(8*10^{2})/g,

since we now that g=9.8m/s^{2} we get that the mass is

m=81.6kg.

Now we can use Newton's law of universal gravitation

F=G\frac{Mm}{r^{2}},  

where m is the mass of the astronaut and M is the mass of the earth. From Newton's second law we know that

F=ma,

in this case the acceleration is the gravity so

F=mg, (<u>becarefull, gravity at this point is no longer</u> 9.8m/s^{2} <u>because we are not in the surface anymore</u>)

and this get us to

mg=G\frac{Mm}{r^{2}}, where mg is his new weight.

We need to remember that the mass of the earth is M=5.972*10^{24}kg and its radius is 6.37*10^{6}m.

The total distance between the astronaut and the earth is

r=(6.37*10^{6}+6.37*10^{6})=2(6.37*10^{6})=12.74*10^{6} meters.

Now we can compute his weigh:

mg=G\frac{Mm}{r^{2}},

mg=(6.674*10^{-11})\frac{(5.972*10^{24})(81.6)}{(12.74*10^{6})^{2}},

mg=200.4 N.

5 0
3 years ago
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