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tatyana61 [14]
3 years ago
10

Which statement best describes the relationship between an object's density and its index of refraction? as the optical density

increases, the refractive index decreases. as the tendency of the atoms to absorb energy before reemitting it increases, the refractive index increases. as the mass per unit volume of the substance increases, the refractive index decreases. as the physical density of the substance increases, the refractive index increases.
Physics
2 answers:
tino4ka555 [31]3 years ago
7 0

Answer:

as the tendency of the atoms to absorb energy before reemitting it increases, the refractive index increases.

Explanation:

The process of being absorbed and re-emitted by the atoms of the material decreases the speed of light from one end of the medium to the other. Therefore, the higher the absorption, the lower its speed in any medium with respect to the speed of light in a vacuum. The index of refraction indicates how slow the light in the material is compared to its speed in a vacuum. Thus, if the atoms absorb more energy before reemitting it increases, the refractive index increases

babunello [35]3 years ago
4 0
For future references, the answer is B.
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Tanzania [10]

Answer with explanation:

We are given that  

Mass of ball,m_1=75 g=\frac{75}{1000}=0075kg

1 kg=1000 g

Height,h_1=1.6 m

h_2=0.6 m

Horizontal velocity,v_x=2 m/s

Mass of platem_2=400 g=\frac{400}{1000}=0.4 kg

a.Initial velocity of plate,u_2=0

Velocity before impact=u_1=\sqrt{2gh_1}=\sqrt{2\times 9.8\times 1.6}=5.6m/s

Where g=9.8 m/s^2

Velocity after impact,v_1=\sqrt{2gh_2}=\sqrt{2\times 9.8\times 0.6}=3.4m/s

According to law of conservation of momentum  

m_1u_1+m_2u_1=-m_1v_1+m_2v_2

Substitute the values  

0.075\times 5.6+0=-0.075\times 3.4+0.4v_2

0.4v_2=0.075\times 5.6+0.075\times 3.4

v_2=\frac{0.075\times 5.6+0.075\times 3.4}{0.4}=1.69 m/s

Velocity of plate=1.69 m/s

b.Initial energy=\frac{1}{2}m_1v^2_x+m_1gh_1=\frac{1}{2}(0.075)(2^2)+0.075\times 9.8\times 1.6=1.326 J

Final energy=\frac{1}{2}m_1v^2_x+m_1gh_2+\frac{1}{2}m_2v^2_2

Final energy=\frac{1}{2}(0.075)(2^2)+0.075\times 9.8\times 0.6+\frac{1}{2}(0.4)(1.69)^2=1.162 J

Energy lost due to compact=Initial energy-final energy=1.326-1.162=0.164 J

6 0
3 years ago
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Explanation:

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7 0
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Answer:

Explanation:

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6 0
3 years ago
A rectangular block of steel measures 4cm*2cm*1.5cm*. its mass is 93.6g
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Answer:

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5 0
3 years ago
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jeka94

Answer:

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Explanation:

Let us look at each of the choices one by one:

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Nope. To send signals transmitters need antennas, and to receive signals   the receivers need antennas as well.

(2). Transmitters send radio waves, and receivers capture radio waves.

This is true. Transmitters are for transmitting and receivers are for     receiving EM signals.

(3). Transmitters have demodulators, and receivers have modulators.

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(4). Transmitters do not have amplifiers, and receivers have amplifiers.

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Therefore, only the 2nd statement "Transmitters send radio waves, and receivers capture radio waves." is correct.

7 0
3 years ago
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