It is very important to note down all the details that are given in the question. Based on these details the answer can be derived.
Initial velocity of the car (V1) = 0 meters/second
Final velocity of the car (V2) = 40 meters/second
Initial time (T1) = 0 Second
Final time (T2) = 60 seconds (In this case we have converted 1 minute into 60 seconds for the ease of calculation.
Then
Average acceleration = (V2 - V1)/ (T2 - T1) m/s^2
= (40 - 0)/(60 - 0) m/s^2
= 40/60 m/s^2
= 2/3 m/s^2
= 0.67 m/s^2
So the average acceleration of the car is 0.67 meters/second square.
Answer:
-10.9 rad/s²
Explanation:
ω² = ω₀² + 2α(θ - θ₀)
Given:
ω = 13.5 rad/s
ω₀ = 22.0 rad/s
θ - θ₀ = 13.8 rad
(13.5)² = (22.0)² + 2α (13.8)
α = -10.9 rad/s²
Competition can result in territory obtained by one kind of birds, causing the other birds to find somewhere else. There can also be competition in food where one type of bird takes over resulting in other birds finding another habitat leading to a decrease and limitation in the size of a bird population.
The driver speeds up with acceleration <em>a</em> so that
35 m/s = 15 m/s + <em>a</em> (10.0 s)
Solve for <em>a</em> :
20 m/s = <em>a</em> (10.0 s)
<em>a</em> = (20 m/s) / (10.0 s)
<em>a</em> = 2 m/s²