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Amiraneli [1.4K]
3 years ago
15

Some pipe organs create sounds lower than humans can hear. This ""infrasound"" can still create physical sensations. What is the

fundamental frequency of the sound from an open-open pipe that is 32 feet long (a common size for large organs)? What length open-closed tube is necessary to produce this note? Assume a sound speed of 343 m/s.
Physics
1 answer:
Dominik [7]3 years ago
8 0

Answer: 17.59 Hz and 4.87 m

Explanation:

The fundamental frequency of the sound from an open-open pipe is given as

f= \frac{v}{2L}

where v= 343 m/s

L= 32 feet= \frac{32}{3.281} = 9.75 m

So,

f= \frac{343}{2*9.75} = 17.59 Hz

The length of open-closed tube is related to frequency by formula

f= \frac{v}{4L}

or L=\frac{v}{4f}

L= \frac{343}{4*17.59}

L= 4.87 m

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