Explanation:
Solution:
Let the time be
t1=35min = 0.58min
t2=10min=0.166min
t3=45min= 0.75min
t4=35min= 0.58min
let the velocities be
v1=100km/h
v2=55km/h
v3=35km/h
a. Determine the average speed for the trip. km/h
first we have to solve for the distance
S=s1+s2+s3
S= v1t1+v2t2+v3t3
S= 100*0.58+55*0.166+35*0.75
S=58+9.13+26.25
S=93.38km
V=S/t1+t2+t3+t4
V=93.38/0.58+0.166+0.75+0.58
V=93.38/2.076
V=44.98km/h
b. the distance is 93.38km
Correct answer choice is:
C. Volley principle (FREQUENCY MATCHING)
Explanation:
Volley theory declares that groups of neurons of the hearing rule counter to a noise by firing action potentials imperceptibly out of the stage with one another so that when connected, a higher pulse of sound can be encoded and transmitted to the brain to be examined.
Answer:
Solution given:
No of waves[N] =20crests & 20 troughs
=20waves
Time[T]=4seconds
distance[d]=3cm=0.03m
Now
<u>Wave</u><u> </u><u>length</u><u>=</u>3cm=3 ×
<u>Frequency</u>=
==5Hertz
and
Wave speed:wave length×frequency=3 × ×5=1.5 × .
Answer:
calculated the speed of light over a short distance
Explanation:
Albert Michelson <u>was an American physicist who conducted an experiment regarding the speed of light in the air 1880s.</u> He believed in the existence of "aether," a field of space that is deemed necessary for transporting electromagnetic forces. In order to do this, he setup a device in order to accurately measure the speed of light in in aether. His device is now known as <u>"Michelson interferometer." </u><em>The result was actually negative. </em>
In order to make his experiment even more accurate, he collaborated with Edward Morley, a famous American scientist. Although the result failed, together, they were able to improve and come with the a standard length of light. This calculated the speed of light over a short distance, which was the significant result of Michelson's experiment.
Thus, this explains the answer.