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jarptica [38.1K]
3 years ago
7

What is the weight (in pounds) of a 7.0 kilogram bowling ball on earths surface

Physics
1 answer:
alekssr [168]3 years ago
3 0

A bowling ball of 7.0 kg will be weighed around 15.54 lbs (pounds) at the surface of the Earth.

<u>Explanation:</u>

The weight of the bowling ball as given in the question,

W=7.0 \mathrm{kg}

Since we know that the force of gravity acting on an object at the surface of the Earth is 2.22 lb i.e. the object will be weighed as 2.22 lb at the surface of the Earth. Similarly, here in this case;

The weight of the bowling ball,

W=7.0 \mathrm{kg} \times 2.22 \frac{\mathrm{lb}}{\mathrm{kg}}

W=15.54 l b

Hence, the bowling ball will be weighed as 15.54 lbs at the surface of the Earth.

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An object is launched from the top of a building which is 100 m tall (relative to the ground) at a speed of 22 m/s at an angle o
klio [65]

Answer:

3.58\:\mathrm{s}

Explanation:

We can use the kinematics equation \Delta y=v_it+\frac{1}{2}at^2 to solve this problem. To find the initial vertical velocity, find the vertical component of the object's initial velocity using basic trigonometry for right triangles:

\sin28^{\circ}=\frac{y}{22},\\y=22\sin28^{\circ}=10.3283743813\:\mathrm{m/s}

Now we can substitute values in our kinematics equation:

  • \Delta y=-100
  • a=-9.8\:\mathrm{m/s^2} (acceleration due to gravity)
  • v_i=-10.3283743813\:\mathrm{m/s}
  • Solving for t

-100=-10.3283743813t+\frac{1}{2}\cdot -9.8\cdot t^2,\\\\-4.9t^2-10.3283743813t+100=0,\\\\\boxed{t=3.5849312673637455}, t=-5.692762773751501\:\text{(Extraneous)}

6 0
3 years ago
Suppose that, from measurements in a microscope, you determine that a certain bacterium covers an area of 1.50μm2. Convert this
s344n2d4d5 [400]
1.50*10^-6=0.0000015m^2
6 0
3 years ago
How to find out the heat capacity of a material?​
DochEvi [55]

\huge\underline{\underline{\boxed{\mathbb {EXPLANATION}}}}

The heat capacity is given by the expression:

\longrightarrow \sf{\triangle Q= m \triangle C  \triangle   T}

\longrightarrow \sf{Q= \: Heat}

\longrightarrow \sf{M= \: Mass}

\longrightarrow \sf{C= \: Specific \: Heat}

\longrightarrow \sf{T= \: Temperature}

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

\leadsto When the \bm{heat} is measured in the calorimeter, we obtain a value, and since we know the mass of the material and we control the change in \bm{temperature} , we can then determine the specific heat "C" by simply remplazing in the expression.

5 0
2 years ago
Scientists measure which element in order to classify magma?
matrenka [14]
Scientists use Silica to classify magma
6 0
3 years ago
What is the smallest value of n for which the wavelength of a Balmer series line is less than 400 nm
Natasha_Volkova [10]

Answer:

The smallest value is n= 2

Explanation:

The balmer equation is given below

1/λ = R(1/4 - 1/n₂²).

R= 1.0973731568508 × 10^7 m^-1

λ= 400*10^-9 m

(400*10^-9)= 1.0973731568508 × 10^7 (1/4-1/n²)

(400*10^-9)/1.0973731568508 × 10^7

= 1/4 - 1/n²

364.51 *10^-16= 1/4 - 1/n²

1/n²= 1/4 -364.51 *10^-16

1/n² = 0.25-3.6451*10^-14

1/0.25= n²

4= n²

√4= n

2= n

The smallest value is N= 2

7 0
3 years ago
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