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3 years ago

Which of these is a transverse wave? Help pls

Physics

2 answers:

ELEN [110]3 years ago

5 0

Answer:

<h2><em>Option 1 </em></h2>

Explanation:

1st option is the correct answer......

vodka [1.7K]3 years ago

4 0

The correct answer is option 1.

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A 438 gram ball is traveling east at 39 m/s when it is hit by a 2.4 kg softball bat. After being in contact with the bat for 302

leonid [27]

Answer:

The magnitude of the impulse vector of the bat is 29.346 kg.m/s

The direction of the impulse vector of the bat is in the initial direction of the ball before impact

Explanation:

The given parameters are;

The mass of the ball, m₁ = 438 g

The speed of the ball = 39 m/s

The mass of the softball bat = 2.4 kg

The time of contact = 302 ms = 0.302 seconds

The speed of rebound = 28 m/s

The impulse = The change in momentum = Δp = F × Δt = m × Δv

The impulse on the ball = m₁ × Δv = 0.438 × (39 - (-28)) = 29.346 kg·m/s

Given that force of reaction of the bat is in opposite direction but equal to the force of the ball, and the time and the duration of contact with the ball is the same for both the ball and the bat, the impulse vector ore equal and opposite

Therefore, the magnitude of the impulse vector of the bat = 29.346 kg.m/s

The direction of the impulse vector of the bat = The initial direction of the ball before impact.

7 0

3 years ago

Extra Practice In Exercises 1-4, use the diagram. 1. Give two other names for CD. <br>

lana [24]

Answer: I think it’s point cd and line cd

Explanation:

6 0

3 years ago

15 POINTSSS HURRYYY) Carrie is doing an experiment about plants in science class. She has four of the same type of plant. She se

Korolek [52]

Plant is the answer also i just looked this up

5 0

4 years ago

Read 2 more answers

Running at 2 m/s, Bruce the 45 kg quarterback, collides with Biff, the 90 kg tackle, who is traveling at 7 m/s in the other dire

melomori [17]

Given data

*The mass of Bruce is m_1 = 45 kg

*The initial velocity of the Bruce is u_1 = 2 m/s

*The mass of the biff is m_2 = 90 kg

*The initial velocity of the Biff is u_2 = -7 m/s

*The final velocity of the first glider is v_2 = -1 m/s

According to the law of conservation of linear momentum, the total linear momentum of a system remains constant

Applying the law of conservation of momentum as

$\begin{gathered} p_i=p_f \\ m_1u_1+m_2u_2=m_1v_1+m_2v_2 \\ v_1=\frac{m_1u_1+m_2u_2-m_2v_2_{}_{}_{}_{}}{m_1} \end{gathered}$

Substitute the known values in the above expression as

$\begin{gathered} v_1=\frac{(45)(2)+(90)(-7)-(90)(-1)}{45} \\ =-10\text{ m/s} \end{gathered}$

Hence, the speed of the bruce knock backwards is v_1 = -10 m/s

3 0

2 years ago

1. (15 points) Small cart is rolling down an inclined track and accelerating. It fires a ball straight out of the cannon as it m

Elena L [17]

Answer:

Explanation:

This problem can be solved with the conservation of the momentum.

If the ball is fired upward, the momentum before and after the ball is fired must conserve. Hence, the speed of the ball is the same that the speed of the car just in the moment in wich the ball is fired.

Hence, the result depends of the acceleration of the car. If the change in the speed is higher than the speed of the ball, it is probably that the ball will be behind the car or it will come back to the car.

If the ball is fired forward, and if the change in the speed of the car is not enogh, the ball will be in front of the car.

HOPE THIS HELPS!!

5 0

3 years ago