Question

A 0.65 kg rock is projected from the edge of

Answer 1

Answer:

180.45m

Explanation:

Given that

mass m= 0.65kg

let H be height of building

angle of projection =40°

initial velocity  v up = 10.5 sin 40 = 6.75 m/s

horizontal velocity u= 10.5 cos 40 = 8.04 m/s

horizontal distance x = 19.6

x=ut

x= u t =

x= 8.04 t

t=19.6/8.04  = 2.44 seconds

applying the formula

h = H + Vt -1/2gt^2

0 = H + 6.75 * 2.44 - 4.9 * 2.44^2

solving for H we have

0=H + 6.75 * 2.44 - 4.9 * 5.9536

0=H + 6.75 * 2.44 - 29.17264

0=H + 6.75 *-26.73264

0=H -180.44532

H=180.45m