Question

A stationary block of mass 35 Kg is suspended on a string.What is the tension in the string ?( Neglect the mass of the string)

Answer 1

Answer:

Tstring = 343.35 [N].

Explanation:

Since the block is in equilibrium, we can say that the sum of the forces on the Y-axis or vertical is equal to zero.

∑Fy = 0

$T_{string}-W=0$

where:

Tstring = tension of the string [N]

W = weight of the block [N]

And the weight can be calculated multiplying the mass of the block by the gravity acceleration.

Now replacing:

$T_{string}=m*g\\T_{string}=35*9.81\\T_{string}=343.35[N]$