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Alika [10]
3 years ago
11

A stationary block of mass 35 Kg is suspended on a string.What is the tension in the string ?( Neglect the mass of the string)

Physics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

Tstring = 343.35 [N].

Explanation:

Since the block is in equilibrium, we can say that the sum of the forces on the Y-axis or vertical is equal to zero.

∑Fy = 0

T_{string}-W=0

where:

Tstring = tension of the string [N]

W = weight of the block [N]

And the weight can be calculated multiplying the mass of the block by the gravity acceleration.

Now replacing:

T_{string}=m*g\\T_{string}=35*9.81\\T_{string}=343.35[N]

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Two identical cylinders, A and B, contain the same type of gas at the same pressure. Cylinder A has twice as much gas as cylinde
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Answer:

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Explanation:

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where,

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<u>FOR CYLINDER A</u>:

PV/R = (nA)(TA)  _____ eqn (1)

<u>FOR CYLINDER B</u>:

PV/R = (nB)(TB)  _____ eqn (2)

Because, Pressure, Volume are constant for both cylinders.

Comparing eqn (1) and (2)

(nA)(TA) = (nB)(TB)

It is given that the amount of gas in cylinder A is twice as much as the gas in cylinder B. This means the number moles in cylinder A are twice as much as no. of moles in cylinder B.

nA = 2(nB)

using this in eqn:

2(nB)(TA) = (nB)(TB)

TA = (1/2)(TB)

<u>TA = 0.5 TB</u>

Therefore it is clear that the correct option is:

<u>D. TA<TB</u>

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3 years ago
THE WINNER WILL BE AWARDED THE BRAINLIEST PLEASE HELPP
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