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2 years ago

Which system of equations and solution can be used to represent the radius if the mass of the cylinder is 11,000 grams

Physics

1 answer:

drek231 [11]2 years ago

7 0

Explanation:

The mass of a cylinder made of barium with a height of 2 inches depends on the radius of the cylinder as defined by the

function m(r) = 7.18872.

which system of equations and solution can be used to represent the radius if the mass of the cylinder is 11,000 grams?

round to the nearest hundredth of an inch.

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That ratio is called"efficiency". It doesn't need to be a percent.
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2 years ago

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2 years ago

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Dimension equation of work

kkurt [141]

Answer:

Explanation:

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3 years ago

An iron block of density rhoFe and of volume l 3 is immersed in a fluid of density rhofluid. The block hangs from a scale which

PolarNik [594]

Answer:

R=m*g-∀fl*g*l3

Explanation:

<em>An iron block of density rhoFe and of volume l 3 is immersed in a fluid of density rhofluid. The block hangs from a scale which reads W as the weight. The top of the block is a height h below the surface of the fluid. The correct equation for the reading of the scale is</em>

From Archimedes' principle we know that a body when immersed in a fluid, fully or partially, experiences an the upward buoyant force equal to the weight of the fluid displaced. As the body is fully submerged in water, volume of water displaced

density of iron =mass/ volume

rho=m/l3

mass=rhol3

weight fluid=rhofluid*g*Volume

weight of fluid=rhofluid*g*l3

F=∀fl*g*l3

Downward force is weight of iron

w=m*g

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R=w-F

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6 0

3 years ago

water has an index of refraction of 1.33. What is the critical angle for light leaving a pool of water into air? 0 37 90 49

vesna_86 [32]

When light travels from a medium with higher refractive index into a medium with lower refractive index, there is a maximum angle (called critical angle) for which all the light is reflected, so there is no refraction.

The value of the critical angle is given by:
$\theta = \arcsin ( \frac{n_2}{n_1} )$
when n1 is the refractive index of the first medium, while n2 is the refractive index of the second medium. In our case, n1=1.33 (the water) and n1=1.00 (the air). Putting numbers in, we get
$\theta = \arcsin ( \frac{1.00}{1.33} )=49^{\circ}$

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3 years ago