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arlik [135]
3 years ago
14

In a titration experiment, hcl and lioh solutions were used. the initial volume of hcl was 1.25ml and lioh was 2.65 ml. the fina

l volume of hcl was 13.60 ml and lioh was 11.20 ml. if the lioh was 0.140 m what was the molarity of hcl?
Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
3 0
Answer is: <span>the molarity of HCl is </span>0.097 M.
Chemical reaction: LiOH + HCl → LiCl + H₂O.
V(HCl) = 13.60 mL - 1.25 mL = 12.35 mL.
V(LiOH) = 11.20 mL - 2.65 mL = 8.55 mL.
c(LiOH) = 0.140 M.
From chemical reaction: n(LiOH) : n(HCl) = 1 : 1.
c(HCl) · V(HCl) = c(LiOH) · V(LiOH).
c(HCl) = 8.55 mL · 0.140 M / 12.35 mL.
c(LiOH) = 0.097 M. 
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Reaction:
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</span><span>1 mole of HCl = 36,5 g
</span><span>1 mole of NaOH = 40g

</span><span>so, according to the reaction:
</span><span>1 mol HCl = 1 mol NaOH
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answer: 36,5 g HCl (hydrochloric acid)
</u><span> ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
</span><span>next question.
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1 mole of NaCl = 58,5 g
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so, according to the reaction:
1 mole of HCl (36,5 g) <span>----------------- - 1 mole of NaCl (58,5 g)
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</span>1 mole of HCl<span> (36,5 g) ------------------ 1 mole of H2O (18 g)
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