The hypothesis is that
the green coloration of plants is related to sunlight exposure of leaves
The hypothesis is tested by keeping a dark green plant inside a dark closet
The result is that the green coloration faded
The conclusion must be that exposure to sunlight affects the green color of the plants
Answer is: mass od zinc is 392,28 g.
N(Zn) = 3,6·10²⁴.
n(Zn) = N(Zn) ÷ Na.
n(Zn) = 3,6·10²⁴ ÷ 6·10²³ 1/mol.
n(Zn) = 6 mol.
m(Zn) = n(Zn) · M(Zn).
m(Zn) = 6 mol · 65,38 g/mol.
m(Zn) = 392,28 g.
Na - Avogadro number.
n - amount of substance.
M - molar mass.
The quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis is 200 ml.
Solvolysis is a type of nucleophilic substitution or elimination wherein the nucleophile is a solvent molecule. function of SN1 reactions, solvolysis of a chiral reactant provides the racemate.
Calculation :-
using the titration equation,
M₁V₁ = M₂V₂
substituting values
V₁ = M₂ V₂/M₁
= 0.2 × 10 ml /0.01
= 2/0.01 ml
= 200 ml.
A reaction in which the solvent is a reactant, and turns into part of the response product. Hydrolysis of tert-butyl chloride; solvent = water. Fischer esterification reaction; solvent = methanol. related phrases: Alcoholysis, aminolysis.
Learn more about solvolysis here:-brainly.com/question/29555642
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<u>Disclaimer:- your question is incomplete, please see below for the complete question.</u>
Calculate the quantity of 0.01M aq NaOH needed to neutralize the HCl produced by complete solvolysis of the t-BuCl in 10ml of 0.2M t-BuCl in acetone.
I thank that your answer is C.
