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Nesterboy [21]
1 year ago
8

What is the resistance of an electric frying pan that draws 12 amperes of current when connected to 120 Volt circuit

Physics
1 answer:
Blizzard [7]1 year ago
5 0

10 ohms

Explanation

the resistance of an electric circuit is given by:

\begin{gathered} R=\frac{V}{I} \\ where\text{ R is the resitance} \\ Vi\text{s the voltage} \\ I\text{ is the current} \end{gathered}

so

Step 1

a) let

\begin{gathered} R=R \\ V=120\text{ volts} \\ I=12\text{ Amperes} \end{gathered}

b) now, replace in the expression

\begin{gathered} R=\frac{V}{I} \\ R=\frac{120\text{ volt}}{12\text{ Amp}} \\ R=10\text{ ohms} \end{gathered}

therefore, the answer is

10 ohms

I hope this helps you

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Sarah added sugar to her iced tea, but it is not dissolving very quickly. Which can Sarah do to make the sugar dissolve faster?
saw5 [17]
Heat the tea because the heat make the tea's particles move around more dissolving the sugar quicker
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3 years ago
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A peregrine falcon dives at a pigeon. The falcon starts downward from rest with free-fall acceleration. If the pigeon is 56.0 m
goldenfox [79]

 

The solution would be like this for this specific problem:

 

<span>v = ? </span><span>
<span>u = 0.0 m/s </span>
<span>a = 9.8 m/s^2 </span>
<span>s = 56.1 m </span></span>

<span>v^2 = (0.0 m/s)^2 + [2 * (9.8 m/s^2) * (56 m) ] </span><span>
<span>v^2 = 2 * (9.8 m/s^2) * (56 m) </span>
<span>v^2 = 1,097.6 m^2/s^2 </span>
<span>v = SQRT {1,097.6 m^2/s^2 } </span></span>

v = 33.1 m/s

<span>v = u + at </span>

<span>(v - u) / a = t </span>

[ (33.1 m/s) - (0.0 m/s) ] / (9.8 m/s^2) = 3.38 seconds

If the pigeon is 56.0 m below the initial position of the falcon, it will take 3.38 seconds for the falcon to reach the pigeon. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

4 0
3 years ago
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Calculate the mass of wood that has the same energy as 1 g of oil
san4es73 [151]

2.3 grams of wood has the same energy as 1g of oil.

The majority of wood and wood waste used as fuel in the United States is used by industry. Manufacturers of paper and wood products are the biggest industrial users. They produce steam and electricity from waste from paper and lumber mills, which saves money by lowering the number of other fuels and electricity they need to buy to run their facilities.

There are numerous power plants that primarily burn wood to produce electricity in the electric power sector, and some coal-burning power plants burn wood chips along with coal to cut down on sulfur dioxide emissions. The primary purpose of wood consumption in the business sector is heating.

To learn more about wood please visit-

brainly.com/question/10967023

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3 0
2 years ago
two masses are kept 2 metre apart there is gravitational force of 2 Newton what is the gravitational force when they are kept at
sukhopar [10]

Answer: 0.5N

Explanation:

Gravitational force is calculated using the formula :

F = Gm1m2/r^2

Where G is the gravitational constant (6.67 × 10^-11)

At a distance 'r' of 2metres apart:

Mass of objects are m1 and m2

Gravitational force 'F1' = 2N

Inputting values into the formula :

2 = Gm1m2 / 2^2 - - - - - (1)

At a distance 'r' of 4meters apart:

Mass of objects are m1 and m2

Gravitational force 'F2' = y

Inputting values

F2 = Gm1m2 / 4^2 - - - - - (2)

Dividing equations 1 and 2

2 = Gm1m2 / 2^2 ÷ F2 = Gm1m2 / 4^2

2 / F2 = (Gm1m2 / 4) / (Gm1m2 / 16)

2 / F2 = (Gm1m2 / 4) × (16 / Gm1m2)

2/F2 = 16 / 4

Cross multiply

2 × 4 = 16 × F2

8 = 16F2

F2 = 8/16

F2 = 0.5N

7 0
3 years ago
A bag of sugar weighs 3.50 lb on Earth. What would it weigh in newtons on the Moon, where the free-fall acceleration isone-sixth
Alex73 [517]

Answer:

F_{Earth}= 15.57 N

F_{Moon}= 2.60 N

F_{Uranus}= 16.98 N

The mass of the bag is the same on the three planets. m=1.59 kg

Explanation:

The weight of the sugar bag on Earth is:

g=9.81 m/s²

m=3.50 lb=1.59 kg

F_{Earth}=m·g=1.59 kg×9.81 m/s²= 15.57 N

The weight of the sugar bag on the Moon is:

g=9.81 m/s²÷6= 1.635 m/s²

F_{Moon}=m·g=1.59 kg× 1.635 m/s²= 2.60 N

The weight of the sugar bag on the Uranus is:

g=9.81 m/s²×1.09=10.69 m/s²

F_{Uranus}=m·g=1.59 kg×10.69 m/s²= 16.98 N

The mass of the bag is the same on the three planets. m=1.59 kg

5 0
2 years ago
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