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3 years ago

6

AWhich property of a gas affects the rate at which it spreads throughoutlaboratory?

1 answer:

balu736 [363]3 years ago

5 0

Answer:

Diffusion is faster at higher temperatures because the gas molecules have greater kinetic energy. Effusion refers to the movement of gas particles through a small hole. Graham's Law states that the effusion rate of a gas is inversely proportional to the square root of the mass of its particles

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Element X reacts with chlorine to form an ionic compound that has a formula of XCl2. To which group could element X belong?(1) G

kap26 [50]

Chlorine has a charge -1. It means that X is +2 so that the formula is XCl2. Group 2 is the correct answer.

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You decide to clean the bathroom. You notice that the shower is covered in a strange green slime. You decide to try to get rid o

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3

Explanation:

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Which element has 32 protons in its nucleus? <br> phosphorus <br> cobalt<br> germanium<br> sulfur

eduard

<span>Germanium is the element that has 32 protons in its nucleus.</span>

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3 years ago

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I have to show my work after I find the atomic weight of each element please help !!

wariber [46]

Explanation:

For all of the questions, do the following calculation

$\frac{isotope \: \times abundance}{100} + \frac{isotope \: \times abundance}{100} ...$

As an example, I'll do question 1

$\frac{204 \times 1.480}{100} + \frac{206 \times 23.6}{100} + \frac{207 \times 22.6}{100} + \frac{208 \times 52.3}{100} = 207.20$

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3 years ago

A metal crystallizes in a body-centered cubic unit cell. The radius of one atom = 2.30 x 10 -8 cm. The density of the metal is 0

maw [93]

Answer:

25.41 g/mol is molar mass of metal.

Explanation:

Number of atom in BCC unit cell = Z = 2

Density of metal = $0.867 g/cm^3$

Edge length of cubic unit cell= a = ?

Radius of the atom of metal = r = $2.30\times 10^{-8} cm$

$a=2\times r=2\times 2.30\times 10^{-8} cm=4.60\times 10^{-8} cm$

Atomic mass of metal =M

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density

Z = number of atom in unit cell

M = atomic mass

$(N_{A})$ = Avogadro's number

a = edge length of unit cell

On substituting all the given values , we will get the value of 'a'.

$0.867 g/cm^3=\frac{2\times M}{6.022\times 10^{23} mol^{-1}\times (4.60\times 10^{-8} cm)^{3}}$

$M = 25.41 g/mol$

25.41 g/mol is molar mass of metal.

6 0

3 years ago