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3 years ago

AWhich property of a gas affects the rate at which it spreads throughoutlaboratory?

Chemistry

1 answer:

balu736 [363]3 years ago

5 0

Answer:

Diffusion is faster at higher temperatures because the gas molecules have greater kinetic energy. Effusion refers to the movement of gas particles through a small hole. Graham's Law states that the effusion rate of a gas is inversely proportional to the square root of the mass of its particles

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When 0.5141 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.823 °C to 29.419 °C

natka813 [3]

Answer:

$\Delta_{r}U$ of the reaction is -6313 kJ/mol

$\Delta_{r}H$ of the reaction is -6312 kJ/mol

Explanation:

$Temperature\,\,change= \Delta U = 29.419-25.823 =3.506^{o}C$

$q_{cal}= C \times \Delta T$

$=5.861 \times 3.596 = 21.076\,kJ$

$q_{rxn}= -q_{cal}= -21.076\,kJ$

$\Delta_{r}U= -21.076 \times \frac{154}{0.5141}= -6313\, kJ/mol$

Therefore, $\Delta_{r}U$ of the reaction is -6313 kJ/mol.

The chemical reaction in bomb calorimeter is as follows.

$C_{12}H_{10}(s)+\frac{27}{2}O_{2}(g)\rightarrow 12CO_{2}(g)+5H_{2}O(g)$

$Number\,of\,moles\Delta n=(12+5)-\frac{27}{2}=3.5$

$\Delta_{r}H=\Delta E+ \Delta n. RT$

$=-6313+3.5\times 8.314\times 10^{-3} \times 3.596=-6312\,kJ/mol$

Therefore, $\Delta_{r}H$ of the reaction is -6312 kJ/mol.

3 0

3 years ago

Question 9 (2 points)

KonstantinChe [14]

Answer:

0.39 moles

Explanation:

To find how many moles are in 50.0 g of CaC₂O₄ you divide the grams of the sample by the molar mass of the compound;

$\frac{50.0 g}{128.097 g/mol}$ =0.39 mol

The grams cancel out and you are left with moles!

I hope this help ^-^

7 0

2 years ago

Read 2 more answers

How many grams is 2.3 mol of li

Paha777 [63]

15.9643 gramns are in 2.3 moles of lithium

4 0

3 years ago

Is 2AI + 3O2 = 2AI2O3 balanced or unbalanced?

Luba_88 [7]

This equation is balanced.

3 0

3 years ago

500mg of iron(ll) complex ferrous bisglycinate hydrochloride was dissolved in dilute H2SO4 and titrated with 0.0200 mol. dm3 KMn

seropon [69]

Using the stoichiometry of the reaction, we can obtain the molar mass of the complex as 276 g/mol. The number of moles iron II as 0.00181 moles and the mass of iron II as 0.1 g.

<h3>Redox reaction</h3>

A redox reaction is one in which there is loss or gain of electrons. The equation of the reaction is 5Fe2+ + MnO4- + 8H+ - - > 5Fe2+ + Mn2+ +4H2O

Number of moles of permanganate = 0.0200 mol. dm3 * 18.10cm3/1000 L

= 0.000362 moles

If 5 moles of iron II reacted with 1 mole of permanganate

x moles of iron II reacts with 0.000362 moles of permanganate

x = 5 moles * 0.000362 moles/ 1 mole

= 0.00181 moles of iron II

Recall that;

Number of moles = mass/molar mass

Molar mass of iron II = 56 g/mol

0.00181 moles = x/56 g/mol

x = 0.00181 moles * 56 g/mol = 0.1 g

If 1 mole of the complex contains 1 mole of iron then;

0.00181 moles = 500 * 10^-3/MM

MM= 500 * 10^-3/0.00181 moles

MM = 276 g/mol

Learn more about stoichiometry: brainly.com/question/9743981

8 0

2 years ago

AWhich property of a gas affects the rate at which it spreads throughoutlaboratory?​

AWhich property of a gas affects the rate at which it spreads throughoutlaboratory?