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AlladinOne [14]
3 years ago
9

Which chemical equation best represents the Law of Conservation of

Chemistry
1 answer:
astra-53 [7]3 years ago
6 0

2H₂ + O₂ ⇒ 2H₂O

<h3>Further explanation</h3>

Conservation of mass states that

<em>In a closed system, the masses before and after the reaction are the same</em>

So it can be concluded

  • mass of the reactants = mass of the products
  • mass cannot be created or destroyed
  • The number of atoms involved in a reaction remains the same⇒ number of moles also the same
  • chemical equation in balanced form

So let's see which of the several options , which one has the same number of atoms on both sides of the equation

2H₂ + O₂ ⇒ 2H₂O

H ⇒ left 4, right 4

O ⇒ left 2, right 2

so the equation is in balance and represents the Law of Conservation of

Mass

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Answer:

Explanation:

We can calculate the volume  of the oxygen molecule as the radius of oxygen molecule is given as 2×10⁻¹⁰m.

We know that volume=4/3×πr³

volume =4/3×π(2.0×10⁻¹⁰m)³

volume=33.40×10⁻³⁰m³

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we know the ideal gas equation as:

PV=nRT

k=R/Na

R=k×Na

PV=n×k×Na×T

n×Na=N

PV=Nkt

p is pressure of gas

v is volume  of gas

T is temperature of gas

N is numbetr of molecules

Na is avagadros number

k is boltzmann constant =1.38×10⁻²³J/K

R is real gas constant

So to calculate pressure using the  formula;

PV=NkT

P=NkT/V

Since there is only one molecule of oxygen so N=1

P=[1×1.38×10⁻²³J/K×300]/[33.40×10⁻³⁰m³

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Answer:

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trial 3: 5.19

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Mass and volume are not directly related. In fact, the relationship between them can be direct or inverse.

Mass is the amount of matter in a substance. Volume is the space a body occupies.

  • A balloon and a stone for example is a typical one.
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Therefore, it is wrong to say a balloon has more mass because it has more volume.

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Answer:

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Secondary alcohols may turn cloudy within five minutes of mixing the solutions. Primary alcohols do not significantly react with Lucas reagent obviously because they do not form stable carbocations.

Therefore we can use the Lucas reagent to distinguish between primary, secondary and tertiary alcohols.

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