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3 years ago

The sum of potential and kinetic energies in the particles of a substance is called _______ energy.

Chemistry

2 answers:

Cloud [144]3 years ago

5 0

I think the sum of potential and kinetic energies in the particles of a substance is called the internal energies ?

White raven [17]3 years ago

5 0

Answer: Mechanical energy

Explanation:

Mechanical energy of a body can be defined as the sum of potential energy and kinetic energy of a system.

The conservation of mechanical energy states that the sum of kinetic energy and potential energy in a system remains constant.

The only condition is the forces acting on it should be conservative forces.

Example: Running of a dog. It is its mechanical energy that is allowing a dog to run by the combination of kinetic and potential energy.

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Uso industrial hidruro mercurico

bonufazy [111]

he arsenic acid or arsenate hydrogen as it is also known to this compound (H 3 AsO 4 ) is the acid form of ion arsenate , AsO4 3- , one anion trivalent in which arsenic has an oxidation state of + 5. Chemically, arsenates behave in a similar way tophosphates .

There is another compound derived from this one that is the arsenious acid or arsenite of hydrogen

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2 years ago

How do you convert ounces to grams

jok3333 [9.3K]

However many ounces you have, just multiply that by 28.34952. The answer to that is the conversion. so 5 ounces is 141.7476. Proof below.

4 0

2 years ago

Read 2 more answers

What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K. The latent heat of vaporization

zzz [600]

Answer:

$\boxed{\text{889 g}}$

Explanation:

The formula relating the mass m of a sample and the heat q to vaporize it is

q = mL, where L is the latent heat of vaporization.

$\begin{array}{rcl}2000 \times 10^{3} \text{ J} & = & m \times \dfrac{2.25 \times 10^{6} \text{ J}}{\text{1 kg}}\\\\m & = & \dfrac{2000 \times \times 10^{3}\text{ kg}}{2.25 \times 10^{6}}\\ & = & \text{0.889 kg}\\\\ & = & \text{889 g}\\\end{array}\\\text{The mass of water is $\boxed{\textbf{889 g}}$}$

5 0

2 years ago

you fill a rigid steel container that has a volume of 20 L with nitrogen gas to a final pressure of 2 x 10^4 kpa at 23 Celsius.

garik1379 [7]

Answer:

4.549 kg.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 2 x 10⁴ kPa/101.325 = 197.4 atm).

V is the volume of the gas in L (V = 20.0 L).

n is the no. of moles of the gas in mol (n = ??? mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 23° C + 273 = 296 K).

∴ n = PV/RT = (197.4 atm)(20.0 L)/(0.0821 L.atm/mol.K)(296 K) = 162.5 mol.

To find the mass of N₂ in the cylinder, we can use the relation:

mass of N₂ = (no. of moles of N₂)*(molar mass of N₂) = (162.5 mol)*(28.0 g/mol) = 4549 g = 4.549 kg.

3 0

2 years ago

Which solution will form a precipitate when mixed with a solution of aqueous na2co3? which solution will form a precipitate when

trapecia [35]

Answer:

$CuCl_{2}(aq.)$ will form a precipitate of insoluble $CuCO_{3}$ when aqueous $Na_{2}CO_{3}$ is added.

Explanation:

According to solubility rule-

all carbonates are insoluble except group IA compounds and $NH_{4}^{+}$

all salts of sodium are soluble

When $Na_{2}CO_{3}$ is added to given solutions, a double displacement reaction takes place in each solution to form a sodium salt and a carbonate salt.

So, in accordance with solubility rule, addition of $Na_{2}CO_{3}$ into $CuCl_{2}(aq.)$ will result precipitation of insoluble $CuCO_{3}$

Reaction: $Na_{2}CO_{3}(aq.)+CuCl_{2}(aq.)\rightarrow 2NaCl(aq.)+CuCO_{3}(aq.)$

4 0

3 years ago