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densk [106]
3 years ago
7

Arjun conducted an experiment in the field related to the rate of percolation. He observed that it took 10 min for 200 mL of wat

er to percolate through the soil sample. Calculate the rate of percolation
Chemistry
1 answer:
Lapatulllka [165]3 years ago
4 0

Answer:

dwdsdsds

Explanation:

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Answer:

No.D is the molecules that has trigonal pyramidal sape

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3 years ago
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What is the measured component of the orbital magnetic dipole moment of an electron with (a) ml = and (b) ml = ?
faust18 [17]

ANSWER:

What is the measured component of the orbital magnetic dipole moment of an electron with the values

(a)  ml=3

(b ) ml= −4

a) -278 x 10^{-23}J/T

b) 3.71 x 10^{-23}J/T

STEP-BY-STEP EXPLANATION:

a) ml= 3

Цorb,z = ml Цв = - (3) * (9.27e - 24) = -278 x 10^{-23}J/T

b) ml= 3

Цorb,z = ml Цв = - (-4) * (9.27e - 24) = 3.71 x 10^{-23}J/T

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3 years ago
Give the symbol for the element with the following orbital diagram:
wel

Answer: 0%

Explanation:

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5 0
3 years ago
How many joules of energy do you have if you have 0.45 L of water in a can and you heat the 23C water to 55C site:socratic.org
Bess [88]

Answer:

Q = 60192 j

Explanation:

Given data:

Volume of water = 0.45 L

Initial temperature = 23°C

Final temperature = 55°C

Amount of heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  55°C - 23°C

ΔT = 32°C

one L = 1000 g

0.45 × 1000 = 450 g

Specific heat capacity of water is 4.18 j/g°C

Q = m.c. ΔT

Q = 450 g.  4.18 j/g°C.  32°C

Q = 60192 j

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