Consider the reaction when aqueous solutions of copper(ii) nitrate and nickel(ii) chloride are combined.
1 answer:
Answer : The reaction that will occur when you combine the aqueous solutions of copper nitrate with nickel chloride is a displacement reaction.
It explained below with the reaction :-
Explanation :
The reaction will give the major product as copper chloride in the form of solid. Rest all the ions will remain in the aqueous form.
It explained below with the reaction :-
Explanation :
The reaction will give the major product as copper chloride in the form of solid. Rest all the ions will remain in the aqueous form.
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Answer:
concentration of = 0.0124 = 12.4 ×10⁻³ M
concentration of = 0.0248 = 2.48 ×10⁻² M
concentration of = 0.4442 M
Explanation:
Equation for the reaction:
⇄
+
Concentration of =
= 0.469
For our ICE Table; we have:
⇄
+
Initial 0.469 0 0
Change - 2x +2x +x
Equilibrium (0.469-2x) 2x x
K =
K =
Since the value pf K is very small, only little small of reactant goes into product; so (0.469-2x)² = (0.469)²
x = 0.0124
∴ at equilibrium; concentration of = 0.0124 = 12.4 ×10⁻³ M
concentration of = 2x = 2 ( 0.0124)
= 0.0248
= 2.48 ×10⁻² M
concentration of = 0.469-2x
= 0.469-2(0.0124)
= 0.469 - 0.0248
= 0.4442 M