Answer:n = PV/RT = 0.923 atm x 0.250 L / (0.082057 x 290.75 K)
. n = 0.00967. mole 0.00967 mole x 6.22x10^23 molecules/mole = 6.02x10^21 molecules of gas
Explanation:
An igneous rock is crushed into little shards of rock called sediment, the sediment is then packed together by other rocks or strong forces, that form together to make a Sedimentary rock.
Reaction of current interest is:
<span>CS2(l) + Cl2(g) </span>→ <span>CCl4(l) + S2Cl2(l)
While balancing the chemical reaction, care must be taken that number of atoms of reactant side is equal to number of reactant on product side.
In present case, There is 1 'C' atom of both reactant and product side
There are 2 'S' atoms on both reactant and product side.
However, there are 2 Cl atoms of reactant side, but 6 Cl atoms on product side.
Hence multiplying Cl2 by 3, would equal the number of Cl atoms on both the sides.
Thus, the balanced reaction is
</span>CS2(l) + 3 Cl2(g) → CCl4(l) + S2Cl2(l)
I believe its A "Air is made up of about 21% oxygen and 78% nitrogen. In this solution, oxygen is the solute and nitrogen is the solvent.
Answer:
concentration of
= 0.0124 = 12.4 ×10⁻³ M
concentration of
= 0.0248 = 2.48 ×10⁻² M
concentration of
= 0.4442 M
Explanation:
Equation for the reaction:
⇄
+ 
Concentration of
=
= 0.469
For our ICE Table; we have:
⇄
+ 
Initial 0.469 0 0
Change - 2x +2x +x
Equilibrium (0.469-2x) 2x x
K = ![\frac{[CO]^2[O]}{[CO_2]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCO%5D%5E2%5BO%5D%7D%7B%5BCO_2%5D%5E2%7D)
K = ![\frac{[2x]^2[x]}{[0.469-2x]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2x%5D%5E2%5Bx%5D%7D%7B%5B0.469-2x%5D%5E2%7D)

Since the value pf K is very small, only little small of reactant goes into product; so (0.469-2x)² = (0.469)²




![x=\sqrt[3]{1.9929*10^{-6}}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B1.9929%2A10%5E%7B-6%7D%7D)
x = 0.0124
∴ at equilibrium; concentration of
= 0.0124 = 12.4 ×10⁻³ M
concentration of
= 2x = 2 ( 0.0124)
= 0.0248
= 2.48 ×10⁻² M
concentration of
= 0.469-2x
= 0.469-2(0.0124)
= 0.469 - 0.0248
= 0.4442 M