Answer: 0.023 liters
Explanation:
Given that,
Original volume of gas (V1) = 25mL
[convert 25mL to liters
If 1000ml = 1L
25ml = 25/1000 = 0.025L]
Original temperature of gas (T1) = 22°C
[Convert 22°C to Kelvin by adding 273
22°C + 273 = 295K]
New volume of gas (V2) = ?
New temperature of gas (T2) = 0°C
[Convert 0°C to Kelvin by adding 273
0°C + 273 = 273K]
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
0.025L/295K = V2/273K
To get the value of V2, cross multiply
0.025L x 273K = 295K x V2
6.825L•K = 295K•V2
Divide both sides by 295K
6.825L•K/295K = 295K•V2/295K
0.023 L = V2
Thus, the new volume of the gas will be 0.023 litres
I think that the answer is B, but I may be wrong...
The average kinetic energy of a collection of gas particles depends on the temperature of the gas and nothing else.
The first and Third graph
