Answer:
Explanation:
Naming of the ionic compounds:-
- The name of the cation is written first and the the name of the anion is written after the name of the cation separated by single space.
- The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
-
In case of transition metals, the oxidation state are written in roman numerals in bracket in front of positive ions.
Hence, given ionic compound:-
Cobalt(II) phosphate
So, Cobalt will have a positive charge of +2
Phosphate is 
So, the formula is :-
Co
2 3
Answer:
The student is Incorrect
Explanation:
Even if you break a magnet the poles still remains same. There is no
difference in the magnet Both north and south pole will be there even if you
cut it in to small pieces when you cut it into pieces, if suppose you break 2
magnets and put north and north together it will repel whereas if there are
different poles like north and south it will attract, so even if you break one
single magnet the different poles will attract, Hence the student is incorrect.
Please mark me as brainliest
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Answer:
It is expensive, largely because of the amount of electricity required in the extraction process. Aluminium ore is called bauxite . The bauxite is purified to produce aluminium oxide, a white powder from which aluminium can be extracted. The extraction is done by electrolysis.
Answer: The value of 
for the weak acid is 
.
Explanation:
First, we will calculate the molarity of HA as follows.
[HA] = 
= 
= 0.015
At equilibrium,
Initial: 0.015 0 0
Change: -x +x +x
Equilibm: 0.015 - x x x
It is given that, at equilibrium
[HA] = 0.015 - x = 0.013
- x = 0.013 - 0.015
= 0.002
Now, expression for of this reaction is as follows.
![k_{a} = \frac{[A^{-}][H_{3}O^{+}]}{[HA]}](https://tex.z-dn.net/?f=k_%7Ba%7D%20%3D%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%7B%5BHA%5D%7D)
= ![\frac{x^{2}}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D%7D%7B%5BHA%5D%7D)
= 
=
Thus, we can conclude that the value of for the weak acid is .
