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kenny6666 [7]
3 years ago
11

An electric field of 1.65 kV/m and a magnetic field of 0.334 T act on a moving electron to produce no net force. If the fields a

re perpendicular to each other, what is the electron's speed?

Physics
2 answers:
Debora [2.8K]3 years ago
7 0

Explanation:

Below is an attachment containing the solution

Blizzard [7]3 years ago
6 0

Answer:

4940.12 m/s

Explanation:

For the net force on the moving electron to be zero, the Magnetic force must then match the electric force.

Magnetic force = Electric force

Magnetic force = qvB

Electric force = Eq

qvB = Eq

v = (E/B)

E = Electric field = 1.65 kV/m = 1650 V/m

B = Magnetic field = 0.334 T

v = (1650/0.334)

v = 4940.12 m/s

Hope this helps!!

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Early black-and-white television sets used an electron beam to draw a picture on the screen. The electrons in the beam were acce
lutik1710 [3]

Answer:

speed of electrons = 3.25 × 10^{7} m/s

acceleration in term g is 3.9 × 10^{17} g.

radius of circular orbit is 2.76 × 10^{-4} m

Explanation:

given data

voltage = 3 kV

magnetic field = 0.66 T

solution

law of conservation of energy

PE = KE

qV = 0.5 × m × v²

v = \sqrt{\frac{2qV}{m}}

v = \sqrt{\frac{2\times 1.6 \times 10^{-19}\times 3}{9.1\times 10^{-31}}

v = 3.25 × 10^{7} m/s

and

magnetic force on particle movie in magnetic field

F = Bqv

ma = Bqv

a = \frac{Bqv}{m}  

a =  \frac{0.67\times 1.6\times 10^{-19}\times 3.25\times 10^7}{9.1\times 10^{-31}}

a = 3.82 × 10^{18} m/s²

and acceleration in term g

a = \frac{3.82\times 10^{18}}{9.81}  

a = 3.9 × 10^{17} g

acceleration in term g is 3.9 × 10^{17} g.

and

electron moving in circular orbit has centripetal force

F = \frac{mv^2}{r}  

Bqv = \frac{mv^2}{r}  

r = \frac{mv}{Bq}  

r = \frac{9.1\times 10^{-31}\times 3.25\times 10^7}{0.67\times 1.6\times 10^{-19}}  

r = 2.76 × 10^{-4} m

radius of circular orbit is 2.76 × 10^{-4} m

8 0
4 years ago
Which of the following is a correct equation for total energy?
Liula [17]

Answer:

kinetic energy + potential energy

6 0
3 years ago
Read 2 more answers
What is the fundamental frequency (in Hz) of a 0.632 m long tube, open at both ends, on a day when the speed of sound is 344 m/s
Greeley [361]

Answer:

f=272.15Hz

Explanation:

Given data

Length of tube L=0.632 m

Speed of sound v=344 m/s

To find

Fundamental frequency f

Solution

The fundamental frequency of the tube can be given as:

f=\frac{v}{2L}\\ f=\frac{344m/s}{2(0.632m)}\\ f=272.15Hz

4 0
4 years ago
Which is produced in a synthesis reaction?
yulyashka [42]

Answer:

Single Compound

Explanation:

A synthesis reaction takes two or more reactants and reacts chemically to turn them all into one substance.  

An example of a synthesis reaction is the reaction that takes place between sodium (Na) and chlorine (Cl) to create table salt.

3 0
3 years ago
Danny lowers the sails on his boat. He paddles upstream at 19 km/hr. The current is still running downstream at 15 km/hr. What i
Molodets [167]

Answer:

4 km/hr

Explanation:

The computation of the actual velocity is shown below:

Because the path of its paddles is opposed to the current direction, the real velocity can be determined by deducting the current velocity to its velocity while paddling

So, the actual velocity is

= Upstream - downstream

= 19 km/hr - 15 km/hr

= 4 km/hr

As we can see it is in positive, so it is an upstream direction  

3 0
3 years ago
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