Answer:
1.758820×10^11(-2.5i-0.8j) m/s^2
Explanation:
From the question, the parameters given are; E=(2.80i+ 5.20j) v/m, a uniform magnetic field,B= 0.400K T, acceleration, a= ??? and velocity vector, v= 11.0i metre per seconds (m/s)...
We can solve this problem using the formula below;
Ma= q[E+V × B] ---------------(1).
Note: q is negative, m= mass of electron.
Making acceleration,a the subject of the formula and substituting the parameters into equation (1);
a= -e/m × (2.5i + 5.2j +11.0i × 0.400K)
a= -e/m × (2.5i+5.2j-4.4j)
a= e/m × (-2.5i - 0.8j)
e/m= 1.758820×10^11 c/kg
Therefore, slotting in the value of charge to mass(e/m) ratio;
a= 1.7588×10^11×(-2.5i-0.8j) m/s^2
