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Romashka [77]
3 years ago
9

What are the activities involved in scientific method?

Physics
1 answer:
klemol [59]3 years ago
6 0
 Ask a Question Do Background Research Construct a Hypothesis Test Your Hypothesis by Doing an Experiment Analyze Your Dat…a and Draw a Conclusion Communicate Your Results
.
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The lower the angle of the slope, ________ the acceleration along the ramp, therefore, the speed at the bottom of a slope will b
pogonyaev

Answer:

Lower

Lower

gsintheta (gsinθ)

Explanation:

The sum of forces resolved parallel to the inclined plane is given by;

F - mgsinθ = 0

ma - mgsinθ = 0

ma = mgsinθ

a = gsinθ

Acceleration is proportional to angle of inclination, thus the lower the angle of the slope, lower the acceleration along the ramp.

therefore, the speed at the bottom of a slope will be lower, (velocity is directly proportional to acceleration) and, consequently, the control will be better.

The acceleration along the ramp, is gsintheta (gsinθ)

3 0
3 years ago
A localized impediment to electron flow in a circuit is a:
hichkok12 [17]
This would be the definition of a resistor. These components inhibit or “resist” the flow of a current.

Hope this helps!
8 0
4 years ago
Read 2 more answers
12. A concave lens has a focal length of 10 cm. An object 2.5 cm high is placed 30 cm from the lens. Determine the position and
Nimfa-mama [501]

Answer:

I think 9.5

Explanation:

............

6 0
3 years ago
Jared has a nut sack that weighs 14 ounces when weighed. If Becky puts an amount of force on them, x , what is the equation that
topjm [15]
X+14 bc that’s what it will equal.
6 0
3 years ago
water has an index of refraction of 1.33. What is the critical angle for light leaving a pool of water into air? 0 37 90 49
vesna_86 [32]
When light travels from a medium with higher refractive index into a medium with lower refractive index, there is a maximum angle (called critical angle) for which all the light is reflected, so there is no refraction.

The value of the critical angle is given by:
\theta = \arcsin ( \frac{n_2}{n_1} )
when n1 is the refractive index of the first medium, while n2 is the refractive index of the second medium. In our case, n1=1.33 (the water) and n1=1.00 (the air). Putting numbers in, we get
\theta = \arcsin ( \frac{1.00}{1.33} )=49^{\circ}
6 0
3 years ago
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