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Virty [35]
2 years ago
9

A 6000 kg rocket is launched vertically from the ground. If the exhaust speed is 1000 m/s, how much gas must be ejected each sec

ond if the thrust is to equal the magnitude of the gravitational force on the rocket
Physics
1 answer:
MrMuchimi2 years ago
3 0

Answer: 60kg/sec

Explanation:

From the question, the mass is given as:

Mass, m = 6000kg

The formula for thrust us calculated as:

F = u × dt/dm

We then equate thrust = weight. This will be:

1000 × dt/dm =mg

1000 × dt/dm = 6000 × 10

1000 × dt/dm = 60000

dt/dm = 60,000/1,000

dt/dm = 60kg

Therefore, the gas ejected per second will be 60 kg/s

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svlad2 [7]
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3. Continue separating the other items.
3 0
3 years ago
Por favor, necesito ayuda urgente 4. vectores perpendiculares de 25 y 40 unidades cada uno. Hallar gráfica y numericamente el ve
Darina [25.2K]

Answer:

4)  R = 47.17 units , 5)  R= 10,29 unidades, 6)   R= 2994,4 km ,    θ = -33,7

Explanation:

Este es un ejercicio de adición de vectores

4) como los vectores son perpendiculares.

Para encontrar la resultante podemos usar el teorema de pitoras

        R =  √ a² + b²

        R = √√ ( 25² + 40²)

        R =  47,17 unidades

5)  Este caso como el angulo es diferente de 90 debemos usar la relación de pitoras completa

        R² =  a² + b² + 2 a b cos θ

donde el angulo es entre los vectores a y b

        R² = 12² + 16² – 2 12 16 cos 40

        R²= 400 – 294,16

       R= 10,29 unidades

6) En este caso los dos desplazamientos son perpendiculares, por lo cual Usamos el teorema de Pitágoras

          R = √ (2400² + 1600²)

          R= 2994,4 km

para el angulo de este desplazamiento usamos trigonometría

           tan θ = y/x

           θ = tan⁻¹ y/x

           θ = tan⁻¹ 1600/(-2400)

           θ = -33,7  

TRASLATE

This is a vector addition exercise

4) as the vectors are perpendicular.

To find the result we can use the Poreor theorem

        R = √ a² + b²

        R = √ (25² + 40²)

        R = 47.17 units

5) This case, as the angle is different from 90, we must use the complete ratio of the pitoras

        R² = a² + b² + 2 a b cos θ

where the angle is between vectors a and b

        R² = 12² + 16² - 2 12 16 cos 40

         R² = 400 - 294.16

       R = 10.29 units

6) In this case the two displacements are perpendicular, which is why we use the Pythagorean theorem

          R = √ (2400² + 1600²)

          R = 2,994.4 km

for the angle of this displacement we use trigonometry

           tan θ = y / x

           θ = tan⁻¹ y / x

           θ = tan⁻¹ 1600 / (- 2400)

           θ = -33.7

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Is energy conserved during a fission/fusion reaction?
avanturin [10]

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Explanation:

One liter of water is closest to 1 kilogram. The other options don't make sense because a dime cannot be close to a mass of 1 kilogram, neither an average size banana or an average person

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