Fiber optic cable, twisted pair cable and coaxial cable are three major types of network cables used in communication systems
I believe the answer is the second option.
Answer:
22.89 N
Explanation:
F = 37 N
Let the acceleration in the system is a and f be the force between the tewo blocks.
Apply the Newton's second law
By the free body diagrams
F - f = 7.4 x a .... (1)
f = 12 x a ...... (2)
Adding both of them
37 = 19.4 x a
a = 1.9 m/s^2
Put in equation (2)
f = 12 x 1.9 = 22.89 N
0.0024
Milimetres are before centimetres and centimetres are before metres