Answer: The force acting on the proton of charge 1.5 x10-19 C moving with velocity 1.5 x10-19 C under the influence of a magnetic field of 0.7 T will be 3.15×10^-13 N.
Explanation: To find the answer we need to know more about the Lorentz magnetic force.
<h3>What is the Lorentz magnetic force acting on the proton?</h3>
- Consider a proton of charge q moving with a velocity v in a magnetic field, then the Lorentz magnetic force exerted on the proton can be expressed as,
F= q (v× B)
where, 
is the angle between v and B.
- In the question, it is given that,
because, from the question it is clear that the proton is moving along x axis and the magnetic field is along the y axis.
- Thus, we can find the force acting on the proton as,
Thus, we can conclude that the Lorentz force acting on the proton will be 3.15×10^-13 N.
Learn more about the Lorentz magnetic force here:
brainly.com/question/28047923
#SPJ1
Acceleration points in the same direction as the net force, so to the left.
The direction of velocity can't be determined from this information alone, though. If the object is at rest, it will being moving to the left. If the object is already moving to the left, it will continue doing so and speed up. If it starts off moving to the right, it will continue to move to the right but eventually slow to a stop before starting to move to the left. There are more cases to consider if you're talking about motion in more than one dimension.
Answer:
c = 204 x 5 = 1020 m/s so it travels 1020 meters in 1 second.
Explanation:
Cause he left out the noble gases out of the periodic table for one good reason, 1: He did not know them
