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MAVERICK [17]
3 years ago
8

Is the frictional force the same as the applied force when the net force equals zero?

Physics
1 answer:
DerKrebs [107]3 years ago
6 0

Answer:

Since the net force is to the right (in the direction of the applied force), then the applied force must be greater than the friction force. The friction force can be determined using an understanding of net force as the vector sum of all the forces.

Explanation:

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What is the length of the x-component of the vector shown below?
Mumz [18]

Answer: D. 2.6

Explanation:A P E X

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3 years ago
Why is wood a renewable resource?
sweet-ann [11.9K]

Answer:

Trees grow everywhere, so we always have some

Explanation:

Wood is a renewable resource; trees can be replanted and grown to maturity in place of those that are cut down. As long as the trees are replanted at the same rate as they are cut down wood will be a renewable resource.

6 0
3 years ago
Find the magnitude of the side and the angle. Please help!
-BARSIC- [3]

Answer:

Explanation:

<em>Assuming the triangle is a right triangle,</em>

the magnitude of R can be found using the Pythagorean theorem,

R = sqrt(9.7^2+6^2) = 11.41 m

The angle can be found by arctangent, which is

angle = atan(9.7/6) = 58.26 degrees.

5 0
3 years ago
Acceleration is always measured in meters per second squared. Why is acceleration not measured in meters per second like speed?
Taya2010 [7]

Answer:

Because 'distance per second' is a velocity, not an acceleration.

Explanation:

Because 'distance per second' is a velocity, not an acceleration. For example, at 1 m/s an object is travelling a distance of 1 metre every second. But a rate of acceleration is a steady increase in velocity. So at 1 m/s^2, an object's velocity is increasing by 1 m/s every second.

6 0
3 years ago
A circular loop of wire has radius of 9.50 cmcm. A sinusoidal electromagnetic plane wave traveling in air passes through the loo
m_a_m_a [10]

Answer:

The induced emf  is  \epsilon  = 0.1041 \  V  

Explanation:

From the question we are told that

   The  radius of the circular loop is  r =  9.50 \ cm  =  0.095 \ m

     The  intensity of the wave is  I  =  0.0215 \ W/m^2

      The wavelength is  \lambda =  6.90\ m

Generally the intensity is mathematically represented as

         I  =  \frac{ c *  B^2  }{ 2 * \mu_o  }

Here  \mu_o is the permeability of free space with value  

         \mu_o  =  4 \pi *10^{-7} N/A^2

B is the magnetic field which can be mathematically represented from the equation as

          B  =  \sqrt{ \frac{ 2 *  \mu_o  *  I  }{ c} }

substituting values

          B  =  \sqrt{ \frac{ 2 *  4\pi *10^{-7} *   0.0215  }{ 3.0*10^{8}} }

          B  =  1.342 *10^{-8} \  T

The  area is mathematically represented as

       A =  \pi r^2

substituting values

       A =  3.142 *   (0.095)^2

       A = 0.0284

The angular velocity is mathematically represented as

        w =  2 *  \pi  *  \frac{c}{\lambda }

substituting values          

       w =  2 *  3.142   *  \frac{3.0*10^{8}}{ 6.90 }  

        w =  2.732 *10^{8} rad  \ s^{-1}  

Generally the induced emf is mathematically represented as

        \epsilon  =  N *  B  *  A  *  w * sin (wt )

At maximum induced emf  sin (wt)  =  1

    So

         \epsilon  =  N *  B  *  A  *  w

substituting values

         \epsilon  = 1  *    1.342 *10^{-8}   *  0.0284  *2.732 *10^{8}  

         \epsilon  = 0.1041 \  V  

         

7 0
3 years ago
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