Answer:
8.2 m/s²
Explanation:
m = mass of the block
μ = Coefficient of kinetic friction = 0.17
= Normal force on the block by the ramp
= kinetic frictional force
Force equation perpendicular to ramp surface is given as
Kinetic frictional force is given as
Force equation parallel to ramp surface is given as
m/s²
Answer:
(a) 
(b) 
(c) 44133.5 m
Explanation:
<u>Given:</u>
= initial speed of the rocket in the first stage = 0 m/s
= final speed of the rocket in the first stage
= final speed of the rocket in the second stage
= time interval of the first stage
= time interval of the second stage
= distance traveled by the rocket in the first stage
= distance traveled by the rocket in the second stage
= distance traveled by the rocket in whole time interval
Part (a):
Since the rocket travels at constant acceleration.
Hence, the expression of the rocket's speed at time 
.
Part (b):
In this part also, the rocket moves with a constant acceleration motion.
Hence, the expression of the rocket's speed in the time interval is 
.
Part (c):
For the constant acceleration of rocket, let us first calculate the distance traveled by the rocket in both the time intervals.
Similarly,
Hence, the rocket moves a total distance of 44133.5 m until the end of the second period of acceleration.
Answer:
Given R (t) = 60/(1+t²), ft
/min
To find the amount of air in ft³, during the first min,
R (t) = 60/(1+t²
at t=1min, R is the air amount in ft³/min
Take the integral, and evaluate over [0,1]
Integral Of R (t) = 60/(1+t²) = 60 tan⁻¹(t),
60(Tan⁻¹(1) - Tan⁻¹(0)) = 60(pi/2) = 30 π
Therefore, it means that in the first minute, 30π ft³ of air escaped.
Answer:
K = 4.43 10⁻¹⁸ J
Explanation:
The energy of the atoms on the surface of the sun is ‘
E = K + U
where the potential energy is given by
U = - k q² / r
the total energy is given by the thermal energy
E = k T
let's substitute in the first equation
k T = K - k e² / r
K = kT + k e2 / r
the constant are worth
k the Boltzmann constant k = 1,381 10-23 J / K
k the Coulomb cosntnate k = 8.99 109 N m2 / C2
e the charge of the electron e = 1.6 10-19 C
r the radius of the hydrogen atom r = 0.0529 10-9 m
let's calculate
K = 1.381 10⁻²³ 5500 + 8.99 10⁹ (1.6 10⁻¹⁹)² / 0.0529 10⁻⁹
K = 7.596 10⁻²⁰ + 4.35 10⁻¹⁸
K = 4.43 10⁻¹⁸ J
