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MA_775_DIABLO [31]
3 years ago
10

Titus drives his jetski a distance of 1000 meters in 7.045 seconds. How fast was he moving in meters per second? How fast was he

moving in miles per hour?
Physics
1 answer:
Ksenya-84 [330]3 years ago
5 0

Answer:

a) v = 141.9 m/s

b) v = 317.4 miles/h

Explanation:

a) How fast was he moving in meters per second?

v = \frac{d}{t} = \frac{1000 m}{7.045 s} = 141.9 m/s

Hence, the jet ski is moving at 141.9 meters per second.

b) How fast was he moving in miles per hour?

v = \frac{d}{t} = \frac{1000 m}{7.045 s} = 141.9 m/s*\frac{3600 s}{1 h}*\frac{1 mile}{1609.34 m} = 317.4 miles/h      

Therefore, the jet ski is moving at 317.4 miles per hour.

I hope it helps you!

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The rate of a reaction is the speed at which products form or reactants disappear.<br> T/F
Natali [406]

Answer: TRUE (:

Explanation:

3 0
3 years ago
A mass of 5 kg is moving at 5 m/s when it collides with another mass of 2 kg moving in the same direction at 2 m/s. After the co
Paul [167]

Answer:

4.14 m/s

Explanation:

m¹u¹+m²u²=(m¹+m²)v

5(5)+2(2)=(5+2)v

25+4=7v

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29/7=v

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6 0
3 years ago
Please help on this one
Sphinxa [80]

Since this is a projectile motion problem, break down each of the five kinematic quantities into x and y components. To find the range, we need to identify the x component of the displacement of the ball.

Let's break them down into components.

                X                                Y

v₁     32 cos50 m/s           32 sin50 m/s

v₂     32 cos50 m/s                    ?

Δd             ?                                0

Δt              ?                                ?

a                0                         -9.8 m/s²


Let's use the following equation of uniform motion for the Y components to solve for time, which we can then use for the X components to find the range.

                           Δdy = v₁yΔt + 0.5ay(Δt)²

                                0 = v₁yΔt + 0.5ay(Δt)²

                                0 = Δt(v₁ + 0.5ayΔt), Δt ≠ 0

                                0 = v₁ + 0.5ayΔt

                                0 = 32sin50m/s + 0.5(-9.8m/s²)Δt

                                0 = 2<u>4</u>.513 m/s - 4.9m/s²Δt

                 -2<u>4</u>.513m/s = -4.9m/s²Δt

-2<u>4</u>.513m/s  ÷ 4.9m/s² = Δt

                          <u>5</u>.00s = Δt


Now lets put our known values into the same kinematic equation, but this time for the x components to solve for range.

Δdₓ = v₁ₓΔt + 0.5(a)(Δt)²

Δdₓ = 32cos50m/s(<u>5</u>.00s) + 0.5(0)(<u>5</u>.00)²

Δdₓ = 32cos50m/s(<u>5</u>.00s)

Δdₓ = 10<u>2</u>.846


Therefore, the answer is A, 102.9m. According to significant digit rules, neither would be correct, but 103m is the closest to 102.9m so I guess that is what it is.






6 0
3 years ago
Two identical projectiles were projected at 200 km/h the first one is at an angle 60 to the horizontal while the second one is a
Setler79 [48]

Answer:

The angle that will have the most range (Goes further) <u>will be the one that is shot with 60 ° with the horizontal. </u>

Since the one that shoots with respect to the vertical, it will only reach higher. And it won't go as far as the horizontal.

Greetings.

Danna.

3 0
3 years ago
Which of the following hardware components allows you to control the position of the screen cursor?
lys-0071 [83]
The answer IS D!!!!!!!!!!!!!!!!!!!!!!!!!!!!
7 0
3 years ago
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