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2 years ago

Someone help ,, I'll give brainliest lolll .

Chemistry

1 answer:

weqwewe [10]2 years ago

5 0

Answer:

the correct answer is c, how easily something catches flames

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A prokaryotic cell does not have

krok68 [10]

Answer:

Explanation:

3 0

2 years ago

0.556 g of a solid white acid are dissolved in water and completely neutralized by the addition of 52.38 mL of 0.396 M NaOH. Cal

Veseljchak [2.6K]

Answer:

$M_{acid}=26.804g/mol$

Explanation:

Hello,

In this case, by knowing that the used NaOH equals in moles the acid (monoprotic) as shown below, during the titration:

$n_{acid}=n_{NaOH}$

By knowing the volume and the concentration of the NaOH, one obtains:

$n_{acid}=0.05238L*0.396\frac{mol}{L}=0.0207mol$

Thus, the molar mass of the acid is computed based on the previously computed moles and the given mass as follows:

$M_{acid}=\frac{m_{acid}}{n_{acid}}=\frac{0.556g}{0.0207mol}=26.804g/mol$

Best regards.

7 0

2 years ago

Your friend had an upset stomach caused by indigestion. His mother explained to him

ddd [48]

Answer:

because it may cause burn that causes acid to build up which causes you to keep having an upset stomach

4 0

2 years ago

An aqueous solution of potassium sulfate (K2SO4) has a freezing point of -2.24

iragen [17]

An aqueous solution of potassium sulfate exhibits colligative properties. Colligative properties are properties that depends on the concentration of a substance in a solution. These properties are freezing point depression, vapor pressure lowering, osmotic pressure and boiling point elevation. For this problem we use the concept of freezing point depression since we are given the freezing point of the solution. Freezing point depression is as:

ΔT = -k(f) x m x i
-2.24 - 0 = -1.86 x m x 3
<span>m = 0.4014

Thus, the molality of the solution is 0.4014.</span>

7 0

3 years ago

Nitrosyl bromide decomposes according to the chemical equation below. 2NOBr(g) 2NO(g) + Br2(g) 1.00 atm of NOBr is sealed in a f

Andrew [12]

Given :

2NOBr(g) - -> 2NO(g) + Br2(g)

Initial pressure of NOBr , 1 atm .

At equilibrium, the partial pressure of NOBr is 0.82 atm.

To Find :

The equilibrium constant for the reaction .

Solution :

2NOBr(g) - -> 2NO(g) + Br2(g)

t=0 s 1 atm 0 0

$t=t_{eqb}$ 1( 1-2x) 2x x

So ,

$1-2x=0.82\\\\x=0.09$

At equilibrium :

$K_{eq}=\dfrac{[NO]^2[br_2]}{[NOBr]^2}\\\\K_{eq}=\dfrac{0.18^2\times 0.9}{0.82^2}\\\\K_{eq}=0.043\ atm$

Hence , this is the required solution .

3 0

2 years ago