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Yuliya22 [10]
3 years ago
5

Help pls , question is in picture

Chemistry
2 answers:
Nata [24]3 years ago
8 0

Explanation:

IM PRETTY SURE IT IS D !! IF ITS WRONG IM SORRY THAT WHAT

I GOT

RSB [31]3 years ago
8 0
D is definitely correct
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I need answersssss ... worth 20 POINTS!!
tester [92]

Not enough information!

Its pretty simple if you think about it.

7 0
3 years ago
What is an ionic bond
Pani-rosa [81]
Ionic bonding is the complete transfer of valence electron(s) between atoms. It is a type of chemical bond that generates two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion.
7 0
3 years ago
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I need this answer quick please show work
Ainat [17]

Answer:

The answer to your question is 25.2 g of acetic acid.

Explanation:

Data

[Acetic acid] = 0.839 M

Volume = 0.5 L

Molecular weight = 60.05 g/mol

Process

1.- Calculate the number of moles of acetic acid

    Molarity = moles / volume

-Solve for moles

    moles = Molarity x volume

-Substitution

    moles = (0.839)(0.5)

-Result

    moles = 0.4195

2.- Calculate the mass of acetic acid using proportions and cross multiplications

                   60.05 g ----------------------- 1 mol

                        x        ----------------------- 0.4195 moles

                        x = (0.4195 x 60.05) / 1

                        x = 25.19 g

3.- Conclusion

25.2 g are needed to prepare 0.500 L of Acetic acid 0.839M

               

4 0
3 years ago
A chunk of copper has a volume of 1.45 mL and a mass of 12.93 grams. What is the density of the chunk of copper?
natta225 [31]

Answer:

Density = 8.92 \ g/mL

Explanation:

The equation for density is:

Density = \frac{mass}{volume}

We plug in the given values:

Density = \frac{12.93 \ g}{1.45 \ mL}

Density = 8.92 \ g/mL

7 0
2 years ago
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Which of the following metals will react with water to produce a metal hydroxide and hydrogen gas? (2 points)
vazorg [7]
The answer would be the first option - k
8 0
3 years ago
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