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chubhunter [2.5K]
3 years ago
8

Sunspots change in number and location during the solar cycle. This phenomenon is connected to

Physics
1 answer:
skad [1K]3 years ago
8 0

Answer:

Continuously changing magnetic field of the Sun

Explanation:

The Sun is made up of plasma and is not solid like our planet. When it rotates the whole of the Sun doesn't rotate with same speed. The equatorial part completes the rotation in just 25 days whereas the poles do it in 35 days. Due to this the magnetic field lines entangle and reorganize them regularly.

The places where the field line exit and enter the surface of the Sun, temperature drops by around 1000 K thus these spots appear black in color and are known as Sun spots.

The magnetic field is not permanent as it will keep changing due to differential rotation. This will result in the change in the no. of location of Sun spots.

If we track the no. of sunspots visible with respect to years we will notice that they follow a cycle of 10.6 years. This is known as Solar cycle in which there comes a solar minima when we see very few sunspots. When it is solar maxima we can see more than 100 sunspots.

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Under normal conditions, the forced expiratory volume is normally _______.
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7 0
3 years ago
Calculate the number of free electrons per cubic meter for some hypothetical metal, assuming that there are 1.3 free electrons p
boyakko [2]

Answer:

The number of free electrons per cubic meter is 7.61\times 10^{28}\ m^{-3}

Explanation:

It is given that,

The number of free electrons per cubic meter is, 1.3

Electrical conductivity of metal, \sigma=6.8\times 10^7\ \Omega^{-1}m^{-1}

Density of metal, \rho=10.5\ g/cm^3

Atomic weight, A = 107.87 g/mol

Let n is the number of  free electrons per cubic meter such that,

n=1.3\ N

n=1.3(\dfrac{\rho N_A}{A})

Where

\rho is the density of silver atom

N_A is the Avogadro number

A is the atomic weight of silver

n=1.3\times (\dfrac{10.5\ g/cm^3\times 6.02\times 10^{23}\ atoms/mol}{107.87\ g/mol})

n=7.61\times 10^{22}\ cm^{-3}

or

n=7.61\times 10^{28}\ m^{-3}

Hence, this is the required solution.

6 0
3 years ago
Suppose you increase your walking speed from 4m/s to 12m/s in a period of 1 s. What is your acceleration?
den301095 [7]
We use the following formula to determine our acceleration:
acceleration = \frac{(final velocity) - (initial velocity)}{time} = \frac{change of velocity}{time}
We normally use letters in this formula, which gives us:
a = \frac{v}{t}

Filling in this formula gives us:
Δv (change of velocity) = 12 - 4 = 8 m/s
t = 1s
a = \frac{8}{1} = 8 m/s^2
So our answer: the acceleration is 8m/ s^{2}
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The element is magnesium ( Mg )
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