Answer : The enthalpy change for the reaction is 1043 kJ/mol.
Explanation :
The given chemical reaction is:

As we know that:
The enthalpy change of reaction = E(bonds broken) - E(bonds formed)
![\Delta H=[(2\times B.E_{C\equiv O})+(1\times B.E_{O\equiv O})]-[2\times B.E_{C=O}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%282%5Ctimes%20B.E_%7BC%5Cequiv%20O%7D%29%2B%281%5Ctimes%20B.E_%7BO%5Cequiv%20O%7D%29%5D-%5B2%5Ctimes%20B.E_%7BC%3DO%7D%5D)
Given:
= 1074 kJ/mol
= 499 kJ/mol
= 802 kJ/mol
Now put all the given values in the above expression, we get:
![\Delta H=[(2\times 1074kJ/mol)+(1\times 499kJ/mol)]-[2\times 802kJ/mol]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%282%5Ctimes%201074kJ%2Fmol%29%2B%281%5Ctimes%20499kJ%2Fmol%29%5D-%5B2%5Ctimes%20802kJ%2Fmol%5D)

Therefore, the enthalpy change for the reaction is 1043 kJ/mol.
a. 2Na Al 03
Equation must have the same number of each element on both sides of the equation.
<u>Answer:</u> The balanced chemical equation is written below.
<u>Explanation:</u>
Galvanization is defined as the process in which a protective layer of zinc is applied to iron or steel to prevent the metal from rusting.
Zinc prevents the oxidation of iron and acts as a reducing agent in the process.
The half reaction for the process follows:
<u>Oxidation half reaction:</u> 
<u>Reduction half reaction:</u> 
Net chemical equation: 
Hence, the balanced chemical equation is written above.
PH = 0.1289<span> for </span>1.50<span> M solution of weak acid with Ka value of </span><span>.73</span>