To determine the number of cups of milk, we first calculate for the volume of the milk needed. Then, we use a conversion factor for the volume from cubic centimeter to cups. From literature, 1 cubic centimeter is equal to 0.0042 cup. We do as follows:
Volume of milk = ( 2.50 kg ) ( 1000 g / 1 kg ) / 1.03 g /cm^3 = 2427.18 cm^3
cups of milk = 2427.18 cm^3 ( 0.0042 cup / 1 cm^3 ) = 10.19 cups
Answer:
Where can you find most of Earth's liquid freshwater?
Explanation:
Over 68 percent of the fresh water on Earth is found in icecaps and glaciers, and just over 30 percent is found in ground water. Only about 0.3 percent of our fresh water is found in the surface water of lakes, rivers, and swamps.
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Answer:
La masa de óxido de carbono iv formado es 44 g.
Explanation:
En esta pregunta, se nos pide calcular la masa de óxido de carbono iv formado a partir de la reacción de masas dadas de carbono y oxígeno.
En primer lugar, necesitamos escribir una ecuación química equilibrada.
C + O2 → CO2
De la ecuación, 1 mol de carbono reaccionó con 1 mol de oxígeno para dar 1 mol de óxido de carbono iv.
Ahora, si marca las masas en la pregunta, verá que corresponde a la masa atómica y la masa molar de la molécula de carbono y oxígeno, respectivamente. ¿Qué indica esto?
Como tenemos una relación molar de 1: 1 en todo momento, lo que esto significa es que la masa de óxido de carbono iv producida también es la misma que la masa molar de óxido de carbono iv.
Por lo tanto, procedemos a calcular la masa molar de óxido de carbono iv Esto es igual a 12 + 2 (16) = 12 + 32 = 44 g Por lo tanto, la masa de óxido de carbono iv formado es 44 g
The polarity of a water molecule
comes from the uneven distribution of electron density of hydrogen and oxygen
atom. The oxygen in the water molecule is more electronegative than the
hydrogen. Water has a partial positive charge near the hydrogen atom and a
partial negative charge near the oxygen atom. The result of this
electrostatic attraction results in the bond called hydrogen bond. Also,
because of this bond, it has the ability to dissolve most of the solutes due to
its polarity and bonding.