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fredd [130]
3 years ago
15

How long will it take for the money to triple? Compounded continuously.

Mathematics
1 answer:
Artemon [7]3 years ago
4 0

The formula for compounded continuously is :

A=Pe^{rt}

Here the Amount triples , so let us say the new amount A=3P

3P=Pe^{rt}

Cancelling P from both sides we get,

3=e^{rt}

Now here we are given rate is 2.75% or 0.0275,

3=e^{0.0275t}

solving for t we get

t=39.95 years

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Tamiku [17]
Jus look and the answer above
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3 years ago
If a town has a density of 8 houses per block and there are 65 blocks in the town, how many houses are in the town?
andriy [413]

Answer:

520 houses

Step-by-step explanation:

Here, we are interested in calculating the number of houses in the town.

We are told that the density is 8 houses per block and there are 65 blocks

The number of houses in the town = density * number of blocks = 65 * 8 = 520 houses

6 0
2 years ago
Please be quick, i need this as soon as possible!
dalvyx [7]

Answer:

I’m pretty sure the answer is a

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the distance between the center of the circle with equation $x^2+y^2=6x-8y+24$ and the point $(-3,-12)$?
kvasek [131]

Answer:

The answer to your question is: 10 units

Step-by-step explanation:

P (-3, -12)

1.- Find the center of the circle

                               x² + y² = 6x - 8y + 24

                              x² - 6x + (   )²  + y² + 8y + (  )²  = 24

                              x² - 6x + (3)² + y² + 8y + (4)² = 24 + 9 + 16

                              (x - 3)² + (y + 4)² = 49

                              Center (3, -4)

2.- Find the distance between the center and the point given

Formula

d = \sqrt{(x2- x1)^{2} + (y2 - y1)^{2} }

Substitution

d = \sqrt{(-3 - 3)^{2} + (-12 +4)^{2} }

d = \sqrt{(-6)^{2} + (-8)^{2} }

d = \sqrt{36 + 64} }

d = \sqrt{100}

d = 10 units

             

3 0
3 years ago
PLS HELP ILL GIVE U BRAINLIST
SCORPION-xisa [38]
<h2>Answer:</h2>

B. |y| = 1.6

<h2>Step-by-step explanation:</h2>

A sketch of the vector is attached to this response.

As shown, the vector lies on the second quadrant and its horizontal and vertical components are given by x and y respectively.

Where;

|x| = v cos θ              -----------------(i)

|y| = v sin θ               -----------------(ii)

and

v = magnitude of the vector = 2.5km/hr

θ = angle that the vector makes with the +x axis = 90° + 50° = 140°

<em>To get the magnitude of the vector's vertical component</em>

<em>Substitute these values into equation(ii) as follows;</em>

|y| = 2.5 sin 140°

|y| =  2.5 x 0.6428

|y| = 1.607

|y| ≅ 1.6 km/hr

Therefore, the vertical component of the vector has a magnitude of 1.6 km/hr.

 

4 0
2 years ago
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