A:- sn(s) => Sn +2(0.24 M) + 2e-
B:- Sn +2 (0.87 M) +2e- => Sn(s)
solution will become more concentrated and solution B become less concentrated
Sn(s)+ Sn +2(0.87 ) ----> Sn(s) + Sn +2(0.24)
E = Eo - 0.0592 / 2 * log [ (0.24 / 0.87 ) ]
E = 0.0 - 0.0592 / 2 * log ( 0.275)
( n=2 two electrons are transferred)
E = -0.0296 * ( - 0.560)
E = 0.0165 volts
8.948 I’m pretty sure I hope this helped
Answer:
as beaker is open so
As ψof solution is lower than the root tissue so water will move out of the root to the solution
Explanation:
Because they are more in close proximity to the core atom's nucleus than lone pairs are, lone pairs reject other lone pairs more strongly than bonding pairs do effect the bond angle.
When a single pair of electrons at the central atom begins to resist the bound pair of electrons, the bond angle decreases and the bonds are slightly shifted inward. It moves existing atoms closer together and modifies their geometry. It's equivalent to include an atom. When there is an increase in back bonding, the bond angle rises. Because the lone pair electrons of the two atoms reject one another, adjacent atoms in a molecule that have lone pair electrons will not be kept together in their bond as securely.
learn more about bond angle here:
brainly.com/question/26587488
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