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Maurinko [17]
3 years ago
8

Methanol (CH3OH) is an organic solvent with a boiling point of 64.5°C. How many grams of mercury(II) bromide (HgBr2, MM = 360.4)

must be dissolved in 542.6 of methanol if the solution has a boiling point of 66.0? The Kb for methanol is 0.86 °C/molal. Assume ideal behavior. (+6 points for submitted work) Your Answer: Answer units​
Chemistry
1 answer:
Softa [21]3 years ago
3 0

Answer:

What is the formula for elevation in boiling point?

Explanation:

The elevation in boiling point (ΔTb) is proportional to the concentration of the solute in the solution. It can be calculated via the following equation. Where, i is the Van't Hoff factor.

...

Boiling Point Elevation Formula.

Solvent Kb value (in oC.kg.mol-1)

Chloroform 3.63

Benzene 2.53

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A light source of wavelength, l, illuminates a metal and ejects photoelectrons with a maximum kinetic energy of 1 eV. A second l
madreJ [45]

Explanation:

From first source, kinetic energy (K.E_{1}) ejected is 1 eV and wavelength of light is \lambda.

From second source, kinetic energy (K.E_{2}) ejected is 4 eV and wavelength of light is \frac{\lambda}{2}.

Relation between work function, wavelength, and kinetic energy is as follows.

                   K.E = \frac{hc}{\lambda} - \phi

where,        h = Plank's constant = 6.63 \times 10^{-34} J.s

                   c = speed of light = 3 \times 10^{8} m/s

Also, it is known that 1 eV = 1.6 \times 10^{-19} J

Therefore, substituting the values in the above formula as follows.

  • From first source,

                      K.E_{1} = \frac{hc}{\lambda} - \phi  

            1 eV = 1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\lambda} - \phi    

    1.6 \times 10^{-19} J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \phi        ........... (1)

  • From second source,

                  K.E_{2} = \frac{hc}{\lambda} - \phi  

          4 \times 1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\frac{\lambda}{2}} - \phi        

                 6.4 \times 10^{-19} J = \frac{2 \times 1.98 \times 10^{-25} J.m}{\lambda} - \phi        ........... (2)        

Now, divide equation (2) by 2. Therefore, it will become

       {6.4 \times 10^{-19}J}{2} = \frac{2 \times 1.98 \times 10^{-25} J.m}{2\lambda} - \frac{\phi}{2}

                3.2 \times 10^{-19}J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \frac{\phi}{2}   ......... (3)

Now, subtract equation (3) from equation (1), we get the following.

                 1.6 \times 10^{-19} = \frac{\phi}{2}

                    \phi = 3.2 \times 10^{-19}

                          = 2 eV

Thus, we can conclude that work function of the metal is 2 eV.

3 0
4 years ago
What is rtp in chemistry?​
valkas [14]

RTP stands for Room Temperature and Pressure.

One mole of any gas has a volume of 24 dm 3 or 24,000 cm 3 at rtp (room temperature and pressure). This volume is called the molar volume of a gas. This equation shows how the volume of gas in dm 3 at rtp is related to the number of moles: volume of gas at rtp = number of moles × 24.

Hope this helped!

6 0
3 years ago
Which of the following instruments is used to measure air pressure?
timama [110]
Barometer, it is used to measure air pressure
5 0
3 years ago
How one atom undergoing fission can cause up to three other atoms to undergo fission.
mamaluj [8]

Answer:

In order to initiate most fission reactions, an atom is bombarded by a neutron to produce an unstable isotope, which undergoes fission. When neutrons are released during the fission process, they can initiate a chain reaction of continuous fission which sustains itself.

7 0
3 years ago
Which of the following chemical formulas represents a total of 12 atoms of oxygen?
9966 [12]

Answer:

3Sn(s04)2

Explanation:bc it cant be anything else

4 0
3 years ago
Read 2 more answers
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