The molar solubility is 7.4×
M and the solubility is 7.4× g/L .
Calculation ,
The dissociation of silver bromide is given as ,
→ 
+ 
S
- S S
Ksp = [ ] [ ] = [S] [ S ] = 
S = √ Ksp = √ 5. 5×
= 7.4×
The solubility =7.4× g/L
The molar solubility is the solubility of one mole of the substance.
Since , one mole of is dissociates and form one mole of each and ion . So, solubility is equal to molar solubility but unit is different.
Molar solubility = 7.4× mol/L = 7.4× M
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In order to determine the increase in boiling point of a solvent due to the presence of a solute, we use the formula:
ΔT = Kb * m * i
Here, Kb is a property of the solvent, so remains constant regardless of the solute. Moreover, because the concentration m has been fixed, this will also not be considered. In order to determine which solute will have the greatest effect, we must check i, the van't Hoff factor.
Simply stated, i is the number of ions that a substance produces when dissolved. Therefore, the solute producing the most ions will be the one causing the greatest change in boiling point temperature.
Answer:
the correct answere to that is q
Answer: 37.6 atm
Explanation:
Given that,
Initial volume of gas (V1) = 19L
Initial pressure of gas (P1) = 9.5 atm
Final volume of gas (V2) = 4.8L
Final pressure of gas (P2) = ?
Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law
P1V1 = P2V2
9.5 atm x 19L = P2 x 4.8L
180.5 atm•L = 4.8L•P2
Divide both sides by 4.8L
180.5 atm•L/4.8L = 4.8L•P2/4.8L
37.6 atm = P2
Thus, the final pressure is 37.6 atmospheres.
Answer:
Solid, Liquid, Gas
Hope it helps! ^^
