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3 years ago

6

Suggest why it might be a good idea to reduce the pressure of the air in car tyres if the car is to be driven over soft sand or

over snow.

1 answer:

vredina [299]3 years ago

6 0

Lowering tire pressure can improve traction by increasing the surface area in contact with the road.

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A cook had a jar containing a sweet food and a jar containing a sour food. The sweet food has a strong attraction between its mo

patriot [66]

Answer:

The sweet food changed because the molecules were able to move fast enough to overcome the attraction between them with its molecules now moving away from each other.

Explanation:

We are told that the sweet food has a strong attraction between its molecules, and the sour food has a weak attraction between its molecules.

This means that the molecules in the sweet food would be moving at a faster rate than in the sour food because of the strong forces of attraction. Therefore, the molecules in the sweet food would be moving far away from each other hence the change of phase.

7 0

3 years ago

An object moves along the x-axis according to the equation x = 3.00t2 – 2.00t + 3.00,

Ray Of Light [21]

Explanation:

x = 3.00 $t^{2}$ – 2.00t + 3.00,

Distance of object at 2 second,

x (t=2) = 3(4) - 2(2) +3

x (t=2) = 12-4 +3

x (t=2) = 11 m

Distance of object at 3 second,

x (t=3) = 3(9) - 2(3) +3

x (t=2) = 27 - 6 + 3

x (t=2) = 24 m

a) the average speed between t = 2.00 s and t = 3.00 s,

Average speed = $\frac{Total distance}{ Total time}$

Average speed = $\frac{x (t=2) + x (t=3)}{3}$

Average speed = $\frac{24+11}{3}$

Average speed = $\frac{35}{3}$

Average speed = 11.66 $\frac{m}{s}$

b) the instantaneous speed at t = 2.00 s and t = 3.00 s,

Instantaneous speed = $\frac{dx}{dt}$

Instantaneous speed(v) = 6t - 2 $\left \{ {{t=2} \atop {t=3}} \right.$

Instantaneous speed,v(t=2 to t=3) = 18-2-12+2

Instantaneous speed, v = 6 $\frac{m}{s}$

c) the average acceleration between t = 2.00 s and t = 3.00 s

average acceleration = $\frac{average velocity}{time}$

average acceleration = $\frac{11.66}{3-2}$

average acceleration = 11.66 $\frac{m}{s^{2} }$

d) the instantaneous acceleration at t = 2.00 s and t = 3.00 s

instantaneous acceleration = $\frac{dv}{dt}$

instantaneous acceleration =6

instantaneous acceleration = 6 $\frac{m}{s^{2} }$

e) for x =0

0 = 3.00 $t^{2}$ – 2.00t + 3.00

a = 3, b=-2, c=3

t= $\frac{-b \pm \sqrt{b^{2} - 4ac} }{2a}$

t= $\frac{2 \pm \sqrt{4 - 36} }{6}$

t= $\frac{2 \pm \sqrt{-32} }{6}$

general solution of this equation gives imaginary value. Hence, the given object is not at rest.

7 0

3 years ago

Read 2 more answers

What is the frequency of X-rays of 10 nm wavelength? 6 x 1016 Hz 3 x 1016 Hz 3.00 Hz 6 x 108 Hz

Evgesh-ka [11]

The frequency of any wave is (wave speed) / (wavelength) .

The speed of light is 3 x 10⁸ m/s.
If the wavelength is 10 nm (10⁻⁸ m) , then the frequency is

(3 x 10⁸) / (10⁻⁸) = <em>3 x 10¹⁶ Hz</em>

That's 30 million gigahertz !

8 0

3 years ago

Definition of Newton’s first law of motion

kipiarov [429]

Newton's first law of motion - sometimes referred to as the law of inertia. Newton's first law of motion is often stated as. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

3 0

3 years ago

Read 2 more answers

Explain why time is an independent and position is a dependent variable in a position versus time graph.

agasfer [191]

Time can be changed in a graph but the position stay the same

3 0

3 years ago