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zhenek [66]
3 years ago
6

A rocket is launched from the surface of Earth with a speed v0 that will allow the rocket to escape the gravitational field of E

arth. The same rocket is now launched from a different planet with the same mass as Earth and four times the radius of Earth. Which of the following is a correct expression for the escape speed from the surface of the new planet?
a. 0.5V.
b. 2V0
c. 0.25v.
d. 0.71V.
e. Vo
Physics
1 answer:
weeeeeb [17]3 years ago
8 0

Answer:

option ( a ) is correct .

Explanation:

Escape velocity on the earth = √ ( 2 GM / R )

where G is universal gravitational constant , M is mass of the earth and R is radius .

V₀ = √ ( 2 GM / R )

escape velocity on the planet where mass is equal is earth's mass and radius is 4 times that of the earth

Radius of the planet = 4 R

escape velocity of planet = √ ( 2 GM / 4R )

= .5 x √ ( 2 GM / R )

= .5 V₀

option ( a ) is correct .

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Answer:

Current amplitude, I = 5.57 A

Explanation:

It is given that,

Effective resistance, R = 22 ohms

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The total impedance of the RL circuit is given by :

Z=\sqrt{R^2+L^2}

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Z = 75.28 ohms

From Ohm's law,

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I=\dfrac{420}{75.28}

I = 5.57 A

So, the current amplitude of the electric motor is 5.57 A. Hence, this is the required solution.

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