The answer is the second choice.
Answer:
The concentration of the solution is 5.8168 ×
mol.
Explanation:
Here, we want to calculate the concentration of the solution.
The unit of this is mol/dm^3
So the first thing to do here is to calculate the number of moles of the solute present, which is the number of moles of AlCO3
The number of moles = mass/molar mass
molar mass of AlCO3 = 27 + 12 + 3(16) = 27 + 12 + 48 = 87g/mol
Number of moles = 33.4/87 = 0.384 moles
This 0.384 moles is present in 660 L
x moles will be present in 1 dm^3
Recall 1 dm^3 = 1L
x * 660 = 0.384 * 1
x = 0.384/660 = 0.00058168 = 5.8168 * 10^-4 mol/dm^3
Reactivity could be one also toxicity flammability ect
Answer:
the answer for this question is true
26.25g
Explanation:
Given parameters:
Percentage of NaCl in ocean water = 3.5%
Mass of given seawater = 750g
Unknown:
Mass of NaCl in the seawater = ?
Solution:
This is a simple percentage problem:
We have been given that ocean water contains 3.5% of NaCl;
Therefore;
Mass of NaCl in seawater = Percentage of NaCl in ocean water x Mass of seawater
Mass of NaCl in seawater =
x 750g = 26.25g
Learn more:
Percentage brainly.com/question/2917248
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