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lutik1710 [3]
2 years ago
12

A conducting sphere of radius 5. 0 cm carries a net charge of 7. 5 µc. what is the surface charge density on the sphere?

Physics
1 answer:
elena-s [515]2 years ago
3 0

The surface charge density on the sphere is 0.014C/m^{2}.

Given,

r=5.00cm=0.05m, q=7. 5 µc

We know surface charge density σ =q/V=\frac{7.5*10^{-6} }{\frac{4}{3}\pi 0.05^{3} }=0.014C/m^{2}.

<h3>Surface charge density </h3>

It is always important to know how charge is moving in an electric field. These fields will also build up electric charges. Therefore, estimation of the surface charge density is essential for a number of applications. It is also necessary to calculate the surface charge density of an electric object using its volume and surface area. The amount of electric charge that has collected in a given field is measured by the surface charge density. Using the dimensions provided, it determines the amount of electric charge. Dimensions of the electric body could be in the form of length, area, or volume. In one, two, or three dimensions, according to electromagnetism, surface charge density is a measurement of the amount of electric charge present in a given volume of space.

A conducting sphere of radius 5. 0 cm carries a net charge of 7. 5 µc. what is the surface surface charge density on the sphere?

Learn more about surface charge density here:

brainly.com/question/8966223

#SPJ4

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12 seconds after starting from rest a frewly falling cantaloupe has a speed of
adoni [48]

Answer:

<em>The cantaloupe has a speed of 117.6 m/s</em>

Explanation:

<u>Free Fall Motion</u>

It occurs when an object falls under the sole influence of gravity. Any object that is being acted upon solely by the force of gravity is said to be in a state of free fall. Free-falling objects do not face air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is g = 9.8 m/s^2.

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The cantaloupe has been dropped from rest. We are required to find the speed after t=12 seconds.

Calculate the final speed:

vf=9.8 * 12 = 117.6 m/s

The cantaloupe has a speed of 117.6 m/s

3 0
3 years ago
Anna is sitting in a moving cart and throws a ball straight up. Theoretically, the ball should land in the cart, but it lands on
Likurg_2 [28]

Answer:

Reason for the difference in the ranges of the ball and the cart:

"the average speed of the cart is less than the instant speed of the cart at the time of throwing the ball".

Explanation:

Assuming that the air friction is negligible.

Given that the ball lands on the ground a little before the cart.

So, the range of the ball is more than the range of the cart in the same time interval.

Let the instant speed of the cart is v m/s  at the time of throwing the ball in the vertically upward direction, so the speed of the ball in the horizontal direction = v m/s.

Let t be the total time of flight of the ball.

As the gravitational force is acting in the downward direction so it will not change the horizontal velocity of the ball.

So, the range covered by the ball = vt m.

Let u be the average speed of the cart for the time t s (same as the time of flight of ball).

So, the distance by the cart = ut m

As the range of the ball is more than the range of the cart in the same time interval, so

vt > ut \\\\\Rightarrow v>u.

So, the reason for the difference in the ranges of the ball and the cart is "the average speed of the cart is less than the instant speed of the cart at the time of throwing the ball".

5 0
3 years ago
Can all rocks be weathered and eroded?how do you know?
skelet666 [1.2K]

Answer:yes

Explanation: Rock can be weathered by ice, acids, animals, temp and etc because the breaking down or dissolving of rock and minerals on the earths surface.

rocks can be eroded by wind, water, ice and, gravity be cause of an action, and friction.

(I think going off of what i learned.)

8 0
3 years ago
Read 2 more answers
on the surface of planet x, a body with a mass of 10 kilograms weighs 40. newtons. the magnitude of the acceleration due to grav
VARVARA [1.3K]
Based on the Newton's second law of motion, the value of the net force acting on the object is equal to the product of the mass and the acceleration due to gravity. If we let a be the acceleration due to gravity, the equation that would allow us to calculate it's value is,

      W = m x a

where W is weight, m is mass, and a is acceleration. Substituting the known values,

    40 kg m/s² = (10 kg) x a

Calculating for the value of a from the equation will give us an answer equal to 4. 

ANSWER: 4 m/s². 
7 0
4 years ago
Need answers fast plz
Len [333]

Answer:

<h2>S.A. = 402.62 m²</h2>

Step-by-step explanation:

We have:

two right triangles with legs 4m and 6m

The area:

A_1=\dfrac{1}{2}(4)(6)=12\ m^2

three rectangles

22m × 6m

The area:

A_2=22\cdot6=132\ m^2

22m × 7.21m

The area:

A_3=22\cdot7.21=158.62\ m^2

22m × 4m

The area:

A_4=22\cdot4=88\ m^2

The Surface Area:

S.A.=2A_1+A_2+A_3+A_4

Substitute:

S.A.=2(12)+132+158.62+88=402.62\ m^2

5 0
4 years ago
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