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11111nata11111 [884]
3 years ago
12

A box with the mass of 20 kg at 5 m is lifted to 20 m. How much work was 7 points done?

Physics
1 answer:
kirza4 [7]3 years ago
3 0

Answer:

2,900\: \mathrm{J}

Explanation:

Work is given by the equation W=F\Delta x where F is force and \Delta x is displacement.

Displacement is defined as change in position. In this case, the box moves from 5m to 20m. Its displacement is 20-5=15\:\mathrm{m}.

The force acting on the box is the force of gravity, given as F_g=mg.

Therefore, the total work done is:

W=F\Delta x=mg\Delta x = 20\cdot 9.81\cdot 15=2,943=\fbox{$2,900\:\mathrm{J}$}(two significant figures).

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b) 68,9 km/h a) picture

Explanation:

In this problem, since velocity is expressed in km/h and time in minutes, we have to convert either time to hours or velocity to km/min. It is easier to use hours.

Using this formula we pass time to hours:

t_{hours}=t_{min}*\frac{1 h}{60 min}\\30min*\frac{1 h}{60 min}=0,5h\\45min*\frac{1 h}{60 min}=0,75h

Now we can plot speed vs time (image 1). The problem says that the driver uses constant speed, so all lines have to be horizontal.

Using the values of the speed we calculate the distance in each interval

d=v*t\\80km/h*0.5h=40km\\100km/h*0.75h=75km

Using these values and the fact that she was having lunch in the third one (therefore stayed in the same position), we plot position vs time, using initial position zero (image 2, distance is in km, not meters).

Finally, we compute the average speed with the distance over time:

v_{average}=\frac{155km}{2.25h}=68.9km/h

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From the Velocity time graph shown:

The positive slope = OA ; This is positive because, it is the point of uniform acceleration on the graph.

Constant slope = AB, the slope here is constant because, AB on the graph is the point of constant velocity.

-ve slope = BC

B) Acceleration of body in path OA.

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