According to the Archimedes principle, if an object is immersed in a fluid, it experiences an apparent loss of weight which is equal to the weight of fluid displaced. The buoyant force which acts in the upward direction opposite to the weight of the object causes the apparent loss in weight. (Hope that helps)
S=ut+a(t^2)/2 = a(t^2)/2 [since u=0] =(v/t)*(t^2)/2 [since a=(v-u)/t=v/t] =vt/2 =180*{25/(60*60)}/2 km = 0.625 km =625 m
<span>a = (v2 - v1)/t= acceleration formula
a = (70 - 0)/7
a = 10 km/hr/sec
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It's better to use as few units as possible.
10 km/hr = 10 km*1000 m/km/(1 hr*3600 sec/hr) = 25/9 m/sec
a= 25/9 m/sec/se</span>
Answer:
Fc = 89.67N
Explanation:
Since the rope is unstretchable, the total length will always be 34m.
From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:
L1+L2=34m
Replacing this value in the previous equation:
Solving for H:
We can now, calculate the angle between L1 and the 2m segment:
If we make a sum of forces in the midpoint of the rope we get:
where T is the tension on the rope and F is the exerted force of 87N.
Solving for T, we get the tension on the rope which is equal to the force exerted on the car:
12 is false I think And I'm not sure about the rest