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Levart [38]
3 years ago
10

______ atoms do not easily react with or form bonds with other atoms.

Physics
1 answer:
Novosadov [1.4K]3 years ago
4 0

Answer:

the Noble gases

Explanation:

the Noble gases are atoms that do not easily react with or form bonds with other atoms

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Which is style of conclusion used in research reports
allsm [11]
A conclusion is, in some ways, like your introduction. You restate your thesis and summarize your main points of evidence for the reader.You can usually do this in one paragraph.
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3 years ago
Water flows on the inside of a steel pipe with an ID of 2.5 cm. The wall thickness is 2 mm, and the convection coefficient on th
Hatshy [7]

Answer:

U = 11.67 W/m² °C

Explanation:

Inner diameter, d = 2.5 cm = 0.025 m

Thickness of the wall, t = 2 mm = 0.002 m

thus, the outer diameter, D = d + 2t = 0.025 + 2 x 0.002 = 0.029 m

h_i =500 W/m^2.^oC

h_0 =12 W/m^2.^oC

Now, based on outside convection heat transfer

we have

\frac{1}{UA_o}=\frac{1}{h_iA_i}+\frac{1}{h_oA_o}

on rearranging, we get

\frac{1}{U}=\frac{1}{h_i}\frac{A_o}{A_i}+\frac{1}{h_o}

where, A_i\ \textup{and}\ A_o are the perimeter respective to inner and and outer diameter

on substituting the values, we get

\frac{1}{U}=\frac{1}{500}\frac{0.029^2}{0.025}+\frac{1}{12}

or

U = 11.67 W/m² °C

6 0
3 years ago
Scientific notation is a method of expressing very small and very large numbers *<br><br> yes<br> No
mars1129 [50]
The answer is yes:)
Scientific notation is the expression of a number in the form of x * 10^x
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4 years ago
How much time would it take for an
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36 and a half hours

Explanation:

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4 years ago
A window has a glass surface of 2907 cm2 and a thickness of 5.6 mm. Find the rate of energy transfer by conduction through this
butalik [34]

Answer:

2.30714 W

-16.38071 W

Explanation:

k = Heat conduction coefficient = 0.8 W/(m·°C)

A = Area = 2907 cm²

l = Thickness = 5.6 mm

T_2 = Outside temperature

T_1 = Inside temperature

Rate of heat transfer is given by

Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 2907\times 10^{-6}\times (81-71)\times \frac{5}{9}}{5.6\times 10^{-3}}\\\Rightarrow Q=2.30714\ W

The rate of energy transfer is 2.30714 W

Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 2907\times 10^{-6}\times (0-71)\times \frac{5}{9}}{5.6\times 10^{-3}}\\\Rightarrow Q=-16.38071\ W

The rate of energy transfer is -16.38071 W

7 0
3 years ago
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