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4 years ago

A solid object has a density of 0.75 g/mL, in which liquid(s) will it sink? SUPPORT your answer.

1 answer:

3 0

The object will sink in any liquid whose density is less than 0.75 g/mL .

A few examples are butane, ether, gasoline, hexane, octane, naphtha, pentane, and propane.

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A care package is dropped from an airplane flying at 1000 m above sea level with a velocity of 200 m/s to an island. If it takes

ikadub [295]

Answer:3000

Explanation:

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3 years ago

How is one second time defined in the si system

Sphinxa [80]

Answer:The place to go for the answer to such an easy question is the SI Brochure, the document which defines the SI and all its units.

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3 years ago

As scientists research, they often find information that does not fit with current theories. What happens when new, contradictor

timofeeve [1]

The correct answer is "C". 'Old theories are adjusted to incorporate all old new information.' This makes the most sense, regarded the old and new information should be taken into consideration.

I hope this helped you!

Brainliest answer is always appreciated!

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3 years ago

Read 2 more answers

to 10 Hz. Superimposed on this signal is 60-Hz noise with an amplitude of 0.1 V. It is desired to attenuate the 60-Hz signal to

givi [52]

Answer:

$G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1$

If we square both sides we got:

$G^2 (1+\frac{f}{f_c})^{2n}= 1$

We divide both sides by $G^2$ and we got:

$(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}$

Now we can apply log on both sides and we got:

$2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})$

And solving for n we got:

$n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}$

And replacing we got:

$n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}$

$n = \frac{4.60517}{3.8918}=1.18$

And since n needs to be an integer the correct answer would be n=2 for the filter order.

Explanation:

For this case we can use the formula for the Butterworth filter gain given by:

[tec] G = \frac{1}{\sqrt{1 +(\frac{f}{f_c})^{2n}}}[/tex]

Where:

G represent the transfer function and we want that G =0.1 since the desired signal is less than 10% of it's value

$f_c = 10 Hz$ represent the corner frequency

$f= 60 Hz$ represent the original frequency

n represent the filter order and that's the variable that we need to find

$G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1$

If we square both sides we got:

$G^2 (1+\frac{f}{f_c})^{2n}= 1$

We divide both sides by $G^2$ and we got:

$(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}$

Now we can apply log on both sides and we got:

$2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})$

And solving for n we got:

$n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}$

And replacing we got:

$n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}$

$n = \frac{4.60517}{3.8918}=1.18$

And since n needs to be an integer the correct answer would be n=2 for the filter order.

7 0

3 years ago

The acceleration due to gravity is lower on the Moon than on Earth. Which of the following is true about the mass and weight of

Naya [18.7K]

Mass is the same, weight is less

<h3>What is the Weight and mass on Moon ?</h3>

As we know that the mass of the object is the measurement of the quantity of the matter that is present in it

So here we can say that if the mass of the object is m then its total quantity of the matter that is present in it is given as

mass = (density) × (volume)

Now for the weight of the object is defined as the force of gravity due to planet

Fg = mg

so the weight of the object is depending on the acceleration due to gravity of the planet

As we know that the gravity of moon is smaller than the gravity of the earth so here weight on the moon will be smaller than the weight on the Earth

Learn more about Weight on Moon here:

brainly.com/question/4080619

#SPJ4

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2 years ago