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Slav-nsk [51]
4 years ago
14

A solid object has a density of 0.75 g/mL, in which liquid(s) will it sink? SUPPORT your answer.

Physics
1 answer:
sukhopar [10]4 years ago
3 0
The object will sink in any liquid whose density is less than 0.75 g/mL .

A few examples are butane, ether, gasoline, hexane, octane, naphtha, pentane, and propane. 
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A tank has the shape of an inverted circular cone with height 16m and base radius 3m. The tank is filled with water to a height
rewona [7]

Answer:

W=17085KJ

Explanation:

From the question we are told that:

Height H=16m

Radius R=3

Height of water H_w=9m

Gravity g=9.8m/s

Density of water \rho=1000kg/m^3

Generally the equation for Volume of water is mathematically given by

 dv=\pi*r^2dy

 dv=\frac{\piR^2}{H^2}(H-y)^2dy

Where

   y is a random height taken to define dv

Generally the equation for Work done to pump water is mathematically given by

 dw=(pdv)g (H-y)

Substituting dv

 dw=(p(=\frac{\piR^2}{H^2}(H-y)^2dy))g (H-y)

 dw=\frac{\rho*g*R^2}{H^2}(H-y)^3dy

Therefore

 W=\int dw

 W=\int(\frac{\rho*g*R^2}{H^2}(H-y)^3)dy

 W=\rho*g*R^2}{H^2}\int((H-y)^3)dy)

 W=\frac{1000*9.8*3.142*3^2}{9^2}[((9-y)^3)}^9_0

 W=3420.84*0.25[2401-65536]

 W=17084965.5J

 W=17085KJ

 

'

'

4 0
3 years ago
James and John dive from an overhang into the lake below. James simply drops straight down from the edge. John takes a running s
liraira [26]

Answer:

Both of them reach the lake at the same time.

Explanation:

We have equation of motion s = ut + 0.5at²

Vertical motion of James : -

          Initial velocity, u = 0 m/s

         Acceleration, a = g

         Displacement, s = h

    Substituting,

                  s = ut + 0.5 at²

                 h = 0 x t + 0.5 x g x t²

                 t_{James}=\sqrt{\frac{2h}{g}}

Vertical motion of John : -

          Initial velocity, u = 0 m/s

         Acceleration, a = g

         Displacement, s = h

    Substituting,

                  s = ut + 0.5 at²

                 h = 0 x t + 0.5 x g x t²

                 t_{John}=\sqrt{\frac{2h}{g}}

So both times are same.

Both of them reach the lake at the same time.

3 0
3 years ago
Object A and Object B are 100 meters apart. If Object A gains some
satela [25.4K]

The gravitational force between the two objects A) It increases.

Explanation:

The gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2} (1)

where

G is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between the objects

In this problem, object A and object B are initially at a distance of

r = 100 m

And at that distance, the force between them is

F

Later, object A gains some mass. We notice from eq.(1) that the gravitational force is directly proportional to the mass: therefore, if the mass of either of the two objects increases, then the gravitational force between them also increases. Therefore, the new force will be larger than the original force:

F' > F

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

7 0
3 years ago
What is required for an electric charge to flow through a wire?
max2010maxim [7]
In order to persuade the electrons in the wire to flow, you need
a potential difference between the ends of the wire.  Then the
electrons will want to get away from the more-negative end and
go to the more-positive end.  If both ends of the wire are at the
same potential, then the electrons have no reason to go anywhere,
and they just stay where they are.

Choice-d says this.
5 0
3 years ago
Read 2 more answers
A ski tow operates on a slope of angle 15.6 ∘ of length 340 m . The rope moves at a speed of 12.7 km/h and provides power for 53
GREYUIT [131]

Answer:

P = 34034.2 Watt

Explanation:

As we know that the slope angle is given as

\theta = 15.6^0

now the weight of the rider along the slope is given as

W = mgsin\theta

W = 69(9.81)sin15.6

W = 182 N

now total weight of all 53 riders along the slope is given as

F = 53 W

F = 9647.5 N

now the speed of the rope is given as

v = 12.7 km/h = 3.53 m/s

now the power required is given as

P = F.v

P = 9647.5(3.53)

P = 34034.2 Watt

3 0
3 years ago
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