Answer:
A is correct option you can go for it
Answer:
for a i think it is choice 2
for b i think it is the first choice
Explanation:
Answer : The value of
of the weak acid is, 4.72
Explanation :
First we have to calculate the moles of KOH.
![\text{Moles of }KOH=\text{Concentration of }KOH\times \text{Volume of solution}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DKOH%3D%5Ctext%7BConcentration%20of%20%7DKOH%5Ctimes%20%5Ctext%7BVolume%20of%20solution%7D)
![\text{Moles of }KOH=3.00M\times 10.0mL=30mmol=0.03mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DKOH%3D3.00M%5Ctimes%2010.0mL%3D30mmol%3D0.03mol)
Now we have to calculate the value of
of the weak acid.
The equilibrium chemical reaction is:
![HA+KOH\rightleftharpoons HK+H_2O](https://tex.z-dn.net/?f=HA%2BKOH%5Crightleftharpoons%20HK%2BH_2O)
Initial moles 0.25 0.03 0
At eqm. (0.25-0.03) 0.03 0.03
= 0.22
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[HK]}{[HA]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BHK%5D%7D%7B%5BHA%5D%7D)
Now put all the given values in this expression, we get:
![3.85=pK_a+\log (\frac{0.03}{0.22})](https://tex.z-dn.net/?f=3.85%3DpK_a%2B%5Clog%20%28%5Cfrac%7B0.03%7D%7B0.22%7D%29)
![pK_a=4.72](https://tex.z-dn.net/?f=pK_a%3D4.72)
Therefore, the value of
of the weak acid is, 4.72
<span>Hydrogen-2 has one neutron; hydrogen-1 has none</span>
Answer:
![m_{H_2O}=8.9g](https://tex.z-dn.net/?f=m_%7BH_2O%7D%3D8.9g)
Explanation:
Hello,
Based on the given reaction, since magnesium and water are in a 1:2 molar ratio at the reactants, we must apply the following stoichiometric factors to compute the complete reaction of the 6.0 g of magnesium:
![m_{H_2O}=6.0gMg*\frac{1molMg}{24.305 gMg}*\frac{2molH_2O}{1molMg} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=8.9g](https://tex.z-dn.net/?f=m_%7BH_2O%7D%3D6.0gMg%2A%5Cfrac%7B1molMg%7D%7B24.305%20gMg%7D%2A%5Cfrac%7B2molH_2O%7D%7B1molMg%7D%20%2A%5Cfrac%7B18gH_2O%7D%7B1molH_2O%7D%20%5C%5C%5C%5Cm_%7BH_2O%7D%3D8.9g)
Best regards.