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anyanavicka [17]
3 years ago
12

-------,-------,--------,and---------- are the four types of main waves

Chemistry
1 answer:
myrzilka [38]3 years ago
4 0

Answer:

As far as i know there are only three types of waves: transverse waves, longitudinal waves, and surface waves. Though maybe I'm incorrect.

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What is the factor of 1024
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1024
4 0
3 years ago
A square painting has a length of 62 cm.<br><br> What is the area of the painting?<br><br> cm²
svetlana [45]

Answer:3844 cm^2

Explanation:

62 squared since it is a square, and area is base times height

3 0
3 years ago
1. 90.0 mL of distilled water is added to a 10.0mL sample of 0.150mol/L sodium
aniked [119]

Answer: dilute

Explanation:

A concentrated solution which is used to prepare solutions of lower concentrations by diluting it with addition of water.

A dilute solution is one which contains lower concentration.

Using Molarity equation:

M_1 =concentration of stock solution = 0.150 mol/L

V_1 = volume of stock solution = 10.0 ml

M_2 = concentration of dilute solution = ?

V_2 = volume of dilute solution = (10.0+90.0) ml = 100.0 ml

0.150\times 10.0=M_2\times 100.0

M_2=0.015mol/L

As the concentration is less than the original concentration, the solution is termed as dilute.

7 0
3 years ago
How do scientists predict the polarity of molecules, the distribution of non-polar and polar molecules?
EastWind [94]

Answer:

Explanation:

Polar molecules interact with other molecules of similar polarity to form solutions. Non-polar molecules do not interact the same way.

8 0
3 years ago
Read 2 more answers
A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products h
statuscvo [17]

Explanation:

First, calculate the moles of CO_{2} using ideal gas equation as follows.

                PV = nRT

or,          n = \frac{PV}{RT}

                = \frac{1 atm \times 4.41 ml}{0.0821 Latm/mol K \times 293 K}      (as 1 bar = 1 atm (approx))

                = 0.183 mol

As,   Density = \frac{mass}{volume}

Hence, mass of water will be as follows.

                Density = \frac{mass}{volume}

             0.998 g/ml = \frac{mass}{3.26 ml}    

                 mass = 3.25 g

Similarly, calculate the moles of water as follows.

        No. of moles = \frac{mass}{\text{molar mass}}

                              =  \frac{3.25 g}{18.02 g/mol}            

                              = 0.180 mol

Moles of hydrogen = 0.180 \times 2 = 0.36 mol

Now, mass of carbon will be as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

          0.183 mol =  \frac{mass}{12 g/mol}            

                              = 2.19 g

Therefore, mass of oxygen will be as follows.

              Mass of O = mass of sample - (mass of C + mass of H)

                                = 3.50 g - (2.19 g + 0.36 g)

                                = 0.95 g

Therefore, moles of oxygen will be as follows.

          No. of moles = \frac{mass}{\text{molar mass}}

                               =  \frac{0.95 g}{16 g/mol}            

                              = 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

                         C              H           O

No. of moles:  0.183        0.36       0.059

On dividing:      3.1           6.1            1

Therefore, empirical formula of the given compound is C_{3}H_{6}O.

Thus, we can conclude that empirical formula of the given compound is C_{3}H_{6}O.            

6 0
3 years ago
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