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geniusboy [140]
3 years ago
8

What kind(s) of intermolecular forces exist in the compounds given below? (a) CH3CH2CH2CH2CH3(l) dispersion forces dipole-dipole

forces hydrogen bonding (c) H2CO(l) dispersion forces dipole-dipole forces hydrogen bonding (b) CH3CH2OH(l) dispersion forces dipole-dipole forces hydrogen bonding (d) O2(l) dispersion forces dipole-dipole forces hydrogen bonding
Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
7 0

Answer:

(a) CH3CH2CH2CH2CH3(l)

  • dispersion

(b) CH3CH2OH(l)

  • Dipole-dipole interaction
  • Dispersion forces
  • Hydrogen bonding

(c) H2CO(l)

  • Dipole-dipole
  • Dispersion

(d) O2(l)

  • Dispersion

Explanation:

Dispersion forces are those forces that occur between two non polar molecules.They form the weakest bonds.Here electrons of one molecule is attracted to the nucleus of the other molecule. Example are;

  • Interaction of two methyl (-CH₃) group
  • Interaction between nitrogen gas , N₂ molecules
  • Interaction between oxygen gas ,O₂ molecules

Dipole-Dipole interaction happens when two polar molecules interact.Positive charges in one molecule is attracted to negative charge of another molecule.Examples

  • Chloroform (CHCl₃)
  • Ammonia (NH₃)

Hydrogen bonding are created when an hydrogen atom bonded to an electronegative atom is attracted to a another electronegative atom.Example is the hydrogen bond between oxygen atom and hydrogen is water (H₂O).

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Vanillin is the common name for 4-hydroxy-3-methoxy-benzaldehyde.

See attached figure for the structure.

Vanillin have 3 functional groups:

1) aldehyde group:  R-HC=O, in which the carbon is double bonded to oxygen

2) phenolic hydroxide group: R-OH, were the hydroxyl group is bounded to a carbon from the benzene ring

3) ether group: R-O-R, were hydrogen is bounded through sigma bonds to carbons

Now for the hybridization we have:

The carbon atoms involved in the benzene ring and the red carbon atom (from the aldehyde group) have a <u>sp²</u> hybridization because they are involved in double bonds.

The carbon atom from the methoxy group (R-O-CH₃) and the blue oxygen's have a  <u>sp³</u>  hybridization because they are involved only in single bonds.

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Determine the boiling point of a 3.70 m solution of phenol in benzene. Benzene has a boiling point of 80.1°C and a boiling point
xeze [42]

Answer: The boiling point of a 3.70 m solution of phenol in benzene is 89.5^0C

Explanation:

Elevation in boiling point:

\Delta T_b=i\times k_b\times m

where,

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