Answer:
Part (i) the magnitude E of the electric field midway between the spheres is 8.71 × 10⁵ N/C
Part (ii) the direction of the electric field is towards the negative charge
Explanation:
Given;
+q = 3.93.90μC, r = 3.50×10⁻²m
-q = −2.40μC, r = 3.50×10⁻²m
magnitude of the electric field is experienced, midway between the spheres at a distance r, r = ¹/₂ × 0.51 = 0.255 m
Electric field due to point charge is given as;
K is coulomb's constant = 8.99 x 10⁹ Nm²/C²
The positive charge on positive x-axis and the negative charge is on negative x-axis.
part (a)
The electric field due to positive charge; +q = 3.93.90μC
The electric field due to negative charge; -q = −2.40μC
From superimposition theorem
The magnitude of the electric field is;
E = E₊ + E₋
E = (5.3919 × 10⁵ + 3.3181 × 10⁵) N/C
E = 8.71 × 10⁵ N/C
Therefore, the magnitude E of the electric field midway between the spheres is 8.71 × 10⁵ N/C
Part (b)
The direction of the electric field is towards the negative charge.